我正在尝试创建一个查询,该查询将返回数据库中的所有节目,这些节目按收藏它的用户数量排序。
简化的工作代码:
from flask import Flask
from flask.ext.sqlalchemy import SQLAlchemy
from sqlalchemy.sql import func
import logging
app = Flask(__name__)
db = SQLAlchemy(app)
logging.basicConfig()
logging.getLogger('sqlalchemy.engine').setLevel(logging.INFO)
favorite_series = db.Table('favorite_series',
db.Column('user_id', db.Integer, db.ForeignKey('users.id')),
db.Column('series_id', db.Integer, db.ForeignKey('series.id')))
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
favorite_series = db.relationship('Serie', secondary=favorite_series,
backref=db.backref('users', lazy='dynamic'))
def __repr__(self):
return '<User {0}>'.format(self.name)
class Serie(db.Model):
__tablename__ = 'series'
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
def __repr__(self):
return '<Serie {0}>'.format(self.name)
u1 = User()
u1.name = 'user1'
u2 = User()
u2.name = 'user2'
u3 = User()
u3.name = 'user3'
s1 = Serie()
s1.name = 'Serie1'
s2 = Serie()
s2.name = 'Serie2'
s3 = Serie()
s3.name = 'Serie3'
s4 = Serie()
s4.name = 'Serie4'
s5 = Serie()
s5.name = 'Serie5'
u1.favorite_series.extend([s1, s3, s5])
u2.favorite_series.extend([s1, ])
u3.favorite_series.extend([s1, s2, s3])
u1.favorite_series.extend([s1, s2])
db.session.add(u1)
db.session.add(u2)
db.session.add(u3)
db.session.add(s1)
db.session.add(s2)
db.session.add(s3)
db.session.add(s4)
db.session.add(s5)
db.create_all()
db.session.commit()
我尝试通过以下方式检索它们:
shows = Serie.query.join(Serie.users).order_by(func.count(Serie.users)).all()
print shows
但这会在 SQL 语法中引发错误,我试图搜索一些东西但无法找到任何有用的东西。
任何帮助,将不胜感激。