3

我在下面有这张表

在此处输入图像描述

我如何制作这样的输出

在此处输入图像描述

我使用此查询完成了上面的输出：

SELECT DISTINCT 
    C.RefVal, 
    C.CalibrationEventID, 
    C1.Result As "Trial One", 
    C2.Result AS "Trial Two", 
    C3.Result AS "Trial Three", 
    C4.Result AS "Trial Four", 
    C5.Result AS "Trial Five" 
FROM CalibrationTrials AS C 
INNER JOIN 
    (SELECT DISTINCT RefVal, Result FROM CalibrationTrials WHERE CalibrationEventID = 'CAL000001' AND RefVal = '1.0010'AND TrialNo = 1) As C1 
ON C1.RefVal = C.RefVal
INNER JOIN 
    (SELECT DISTINCT RefVal, Result FROM CalibrationTrials WHERE CalibrationEventID = 'CAL000001' AND RefVal = '1.0010'AND TrialNo = 2) As C2 
ON C2.RefVal = C.RefVal
INNER JOIN 
    (SELECT DISTINCT RefVal, Result FROM CalibrationTrials WHERE CalibrationEventID = 'CAL000001' AND RefVal = '1.0010'AND TrialNo = 3) As C3 
ON C3.RefVal = C.RefVal
INNER JOIN 
    (SELECT DISTINCT RefVal, Result FROM CalibrationTrials WHERE CalibrationEventID = 'CAL000001' AND RefVal = '1.0010'AND TrialNo = 4) As C4 
ON C4.RefVal = C.RefVal
INNER JOIN 
    (SELECT DISTINCT RefVal, Result FROM CalibrationTrials WHERE CalibrationEventID = 'CAL000001' AND RefVal = '1.0010'AND TrialNo = 5) As C5 
ON C5.RefVal = C.RefVal

WHERE C.CalibrationEventID = 'CAL000001' AND C.RefVal = '1.0010'
ORDER BY C.RefVal, C.CalibrationEventID

显然，使用此查询，输出仅固定为一个 RefVal，即“1.0010”

为 CalibrationEventID 的每个 RefVal 输出 image2 格式的正确查询是什么？

4

1 回答 1

2

以下是如何为查询使用PIVOT子句：

SELECT
  RefVal,
  CalibrationEventID,
  [1] AS [Trial One],
  [2] AS [Trial Two],
  [3] AS [Trial Three],
  [4] AS [Trial Four],
  [5] AS [Trial Five],
  [6] AS [Trial Six]
FROM CalibrationTrials
PIVOT (
  MAX(Result) FOR TrialNo IN ([1], [2], [3], [4], [5], [6])
) AS p

以上假设您的表仅包含 columns RefVal, CalibrationEventID, TrialNo, Result。如果表中有更多列，则应先分别选择这四个，然后应用 PIVOT。这里：

SELECT
  RefVal,
  CalibrationEventID,
  [1] AS [Trial One],
  [2] AS [Trial Two],
  [3] AS [Trial Three],
  [4] AS [Trial Four],
  [5] AS [Trial Five],
  [6] AS [Trial Six]
FROM (
  SELECT
    RefVal,
    CalibrationEventID,
    TrialNo,
    Result
  FROM CalibrationTrials
) AS c
PIVOT (
  MAX(Result) FOR TrialNo IN ([1], [2], [3], [4], [5], [6])
) AS p

这是必需的，因为 PIVOT 查询本质上是一种特殊情况的 GROUP BY 查询。除了隐式Result参与分组之外的所有列。这就是为什么你应该摆脱这种分组中不需要的那些。

这是另一种方法，没有 PIVOT：

SELECT
  RefVal,
  CalibrationEventID,
  MAX(CASE TrialNo WHEN 1 THEN Result END) AS [Trial One],
  MAX(CASE TrialNo WHEN 2 THEN Result END) AS [Trial Two],
  MAX(CASE TrialNo WHEN 3 THEN Result END) AS [Trial Three],
  MAX(CASE TrialNo WHEN 4 THEN Result END) AS [Trial Four],
  MAX(CASE TrialNo WHEN 5 THEN Result END) AS [Trial Five],
  MAX(CASE TrialNo WHEN 6 THEN Result END) AS [Trial Six]
FROM CalibrationTrials
GROUP BY
  RefVal,
  CalibrationEventID
于 2012-05-31T09:31:54.743 回答