mysql - SQL 查询 - 无法比较字段值？

Question

我played_dt在表中有列widget_event_data。 plyed_dt以这种格式保存日期2009-06-16 21:38:07

我想获取played_dt包含2009-06-16的行

有没有办法做到这一点。我该如何为此编写sql查询？

将不胜感激帮助..

score 2 · Accepted Answer

2

WHERE DATE(played_dt) = '2009-06-16'

于 2012-05-31T06:24:28.193 回答

score 2 · Accepted Answer

2

select * from your_table
where played_dt like '2009-06-16%'

于 2012-05-31T06:24:54.180 回答

score 0 · Accepted Answer

0

select * from table where played_dt = '2009-06-16'

将在甲骨文中工作。

于 2012-05-31T06:29:45.850 回答

score 0 · Accepted Answer

使用DATE()功能。试试这个：

select * 
FROM widget_event_data
where DATE(played_dt) = DATE('2009-06-16')

score 0 · Accepted Answer

select * from tableName where played_dt = str_to_date('2009-06-16', '%Y-%m-%d')

5 回答 5