我有一个简单的 Web 服务,它从数据库中获取数据,我想将这些数据作为数据集、字符串、XML 返回。但是 Web 服务 xml 没有得到我返回的类型。问题是,是否可以作为对象和 Web 服务 XML 返回以显示正确的标签。目前它显示此标签 anytype 而不是 string 例如。
这是方法
[WebMethod]
public Object serviceForPostcode(String postCode, String type)
{
/**
*
* create dataset to store query
* convert dataset to required return type
* create types for returned object
*
*
**/
SqlDataAdapter adapter = new SqlDataAdapter();
SqlCommand cmd = new SqlCommand();
SqlConnection conn = new SqlConnection(dbConnection());
/**
*
* -- types--
*
**/
XmlDocument xmlD = new XmlDocument();
StringWriter sw = new StringWriter();
DataSet dataSet = new DataSet();
/**
*
*
**/
// connection and query string
string dbQuery = "SELECT id, address1, address2, address3, address4, address5, post_code, country FROM paf WHERE (post_code = @postCode)";
try
{
cmd.Parameters.Add(new SqlParameter("@postcode",SqlDbType.NChar, 10)).Value = postCode.ToUpper();
cmd.CommandText = (dbQuery);
cmd.CommandType = CommandType.Text;
cmd.Connection = conn;
adapter.SelectCommand = cmd;
adapter.Fill(dataSet,"post codes");
}
catch(Exception e)
{
System.Web.HttpContext.Current.Response.Write(e.Message);
}
finally
{
//close database connection
conn.Close();
}
if (type.Equals("xml", StringComparison.InvariantCultureIgnoreCase))
{
return dataSet.GetXml();
}
else if (type.Equals("string", StringComparison.InvariantCultureIgnoreCase))
{
dataSet.WriteXml(sw);
return sw.ToString();
}
else if(type.Equals("dataset",StringComparison.InvariantCultureIgnoreCase))
{
return "";
}
return "error";
}