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我一直试图在网上寻找我想要的东西，但我运气不佳，所以我想我会在这里问。

是否可以用不同的颜色精确定位并在图表上显示两个图之间存在交叉点的点？

谢谢你提供的所有帮助。

这是代码：

file1 = fopen('C:\Program Files (x86)\Notepad++\avatar1.txt'); % open text file
file2 = fopen('C:\Program Files (x86)\Notepad++\avatar2.txt'); % open text file
file3 = fopen('C:\Program Files (x86)\Notepad++\avatar3.txt'); % open text file

tline1 = fgetl(file1); % read line by line and remove new line characters
tline2 = fgetl(file2); % read line by line and remove new line characters
tline3 = fgetl(file3); % read line by line and remove new line characters

% declare empty arrays
CX1 = [];
CY1 = [];
CZ1 = [];

CX2 = [];
CY2 = [];
CZ2 = [];

CX3 = [];
CY3 = [];
CZ3 = [];


while ischar(tline1) % true if tline is a character array
    temp = cell2mat(textscan(tline1, '<%n,%n,%n>'));

    % convert all the cell fields to a matrix
    CX1 = vertcat(CX1, temp(1));
    CY1 = vertcat(CY1, temp(2));
    CZ1 = vertcat(CZ1, temp(3));

    tline1 = fgetl(file1);
end

while ischar(tline2) % true if tline is a character array
    temp = cell2mat(textscan(tline2, '<%n,%n,%n>'));

    % convert all the cell fields to a matrix
    CX2 = vertcat(CX2, temp(1));
    CY2 = vertcat(CY2, temp(2));
    CZ2 = vertcat(CZ2, temp(3));

    tline2 = fgetl(file2);
end

while ischar(tline3) % true if tline is a character array
    temp = cell2mat(textscan(tline3, '<%n,%n,%n>'));

    % convert all the cell fields to a matrix
    CX3 = vertcat(CX3, temp(1));
    CY3 = vertcat(CY3, temp(2));
    CZ3 = vertcat(CZ3, temp(3));

    tline3 = fgetl(file3);
end

fclose(file1); % close the file
fclose(file2); % close the file
fclose(file3); % close the file

plot3(CX1, CY1, CZ1) % plot the data and label the axises
plot3(CX2, CY2, CZ2)
plot3(CX3, CY3, CZ3)
xlabel('x')
ylabel('y')
zlabel('z') 
grid on
axis square
rotate3d on; % activate interactive mouse rotation
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1 回答 1

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更改颜色很简单，只需在 plot3 命令中添加颜色代码，例如：

plot3(CX1, CY1, CZ1, 'b'); % blue lines/markers
plot3(CX2, CY2, CZ2, 'r'); % red lines/markers
plot3(CX3, CY3, CZ3, 'g'); % green lines/markers

有关颜色代码的更多详细信息，请参阅Matlab Colourspec 页面。

交点可能有点棘手，具体取决于您是想要点的交点（即出现在所有 3 个数据集中的特定点）还是连接点的线的交点。

我认为前者应该相当容易（这是未经测试的，假设CX1等是垂直向量）：

figure; % Open up a new figure
hold on; % This means the everything you plot stays in the figure and is not overwritten

% Plot the original points
plot3(CX1, CY1, CZ1, '-*b'); % blue lines/markers
plot3(CX2, CY2, CZ2, '-*r'); % red lines/markers
plot3(CX3, CY3, CZ3, '-*g'); % green lines/markers

% turn those 1xn vectors into 3xn matrices for each set of points
points1 = [CX1, CY1, CZ1];
points2 = [CX2, CY2, CZ2];
points3 = [CX3, CY3, CZ3];

% Find the intersection of the 3 sets
CX_intersect = intersect( points1, intersect( points2, points3, 'rows'), 'rows');

% Draw a scatter plot of the intersection points. the 'mo' means:
% m: magenta in colour, o: circular markers
scatter3( CX_intersect(:,1),CX_intersect(:,2),CX_intersect(:,3),'mo');

交叉点的工作方式如下：

假设我们有 3 个矩阵，每个矩阵包含许多 3d 点。让我们称它们A为B和C。

A为了找到所有 3 个集合之间的交集，我们首先找到在和中相交的点B。我们现在有一组我们知道在A和中的点B，所以现在我们只需要检查这些点是否C也在。我们通过做另一个交集来做到这一点。

我只是将它们链接成一行代码，这可能不是很有用，所以我道歉。A, B,交叉点的代码C如下：

D = intersect(A,B,'rows') % we use rows because each row represents a 3D point
E = intersect(C,D,'rows') % E is the intersection of the 3 sets.

然后我们可以将 D 代入该行E = ...，我们得到：

E = intersect( intersect(A,B,'rows'), C, 'rows' );

希望有帮助！

于 2012-05-30T13:57:37.323 回答