我有一个查询
SELECT foodjoint_id FROM provider_food_joints WHERE foodjoint_name='".$foodjoint_name."'";
现在我必须从另一个有 foodjoint_id 归档的表中选择所有信息
SELECT * AND foodjoint_name FROM provider_food_joints from menu_item where foodjoint_id = THOSE ID
我必须加入这两个