我正在尝试使用 Jquery 的 .hover() 方法突出显示表行。
我有以下代码：
var x;
var namen;
window.onload = function(){
x = true;
y = true;
$("submitnieuw").observe('click', addturf);
$("submitdelete").observe('click', verwijderturf);
$("stats").on("click", "tr", select);
setInterval(function (){
jQuery("#recent").load("vandaag.php");
if(x){
jQuery("#stats").load("stats.php");
}
}, 10000);
$("tr").not(':first').hover(
function () {
$(this).addClassName("selected");
},
function () {
$(this).removeClassName("selected");
}
);
alert("test");
};
function select(naam){
//highlight the selected list element
if (y){
var name = naam.findElement('tr').id;
if (name !== ""){
x = false;
y = false;
jQuery.ajax('details.php',{
data: {
'Naam': name,
'door': $("door2").value
},
type: 'post',
success: function(data){
$("stats").innerHTML = data;
},
error: ajaxFailure
});
}
}
else{
x = true;
y = true;
jQuery("#stats").load("stats.php");
jQuery("#recent").load("vandaag.php");
}
}
function verwijderturf() {
var box = document.getElementById("naamverwijder");
var naam = box.options[box.selectedIndex].value;
document.getElementById("naamnieuw").selectedIndex=0;
$("redennieuw").value = "";
jQuery.ajax('server.php',{
data: {
'mode': 'verwijderturf',
'naam': naam,
'door': $("door2").value
},
type: 'post',
success: update,
error: ajaxFailure
});
}
function addturf() {
var box = document.getElementById("naamnieuw");
var naam = box.options[box.selectedIndex].value;
document.getElementById("naamnieuw").selectedIndex=0;
var reden = $("redennieuw").value;
$("redennieuw").value = "";
jQuery.ajax('server.php',{
data: {
'mode': 'addturf',
'naam': naam,
'door': $("door2").value,
'reden': reden
},
type: 'post',
success: update,
error: ajaxFailure
});
}
function update(ajax){
jQuery("#stats").load("stats.php");
jQuery("#recent").load("vandaag.php");
}
function ajaxFailure(ajax, exception) {
alert("Error making Ajax request:" +
"\n\nServer status:\n" + ajax.status + " " + ajax.statusText +
"\n\nServer response text:\n" + ajax.responseText);
if (exception) {
throw exception;
}
}
selected 在我的 index.php 中包含的 css 中定义。
这是我的 index.php
<?php
include_once("db.php");
session_start();
if (!isset($_SESSION['uid'])){
header("location:main_login.php");
exit();
}
if (!isset($_SESSION['upass'])){
header("location:main_login.php");
exit();
}
$sql="SELECT * FROM users WHERE Naam='".$_SESSION['uid']."' AND Wachtwoord='".$_SESSION['upass']."'";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
if($count < 1){
header("location:main_login.php");
exit();
}
?>
<?php
$date = date("y-m-d");
$vandaag = mysql_query("SELECT Type, Naam, Reden, Door FROM turfjes WHERE turfjes.Datum = '" . $date . "'");
$names = mysql_query("SELECT Naam From users");
$names2 = mysql_query("SELECT Naam From users");
$names3 = mysql_query("SELECT Naam From users");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Tomaten turfjes pagina | 258</title>
<link rel="stylesheet" type="text/css" href="css/reset.css" media="all" />
<link rel="stylesheet" type="text/css" href="css/style.css" media="all" />
<script type="text/javascript" src="js/jquery.js"></script>
<script>
jQuery.noConflict();
</script>
<script src="js/prototype.js" type="text/javascript"> </script>
<script src="js/scriptaculous.js" type="text/javascript"></script>
<script src="js/script.js" type="text/javascript"> </script>
</head>
<body>
<div id="container">
<div id="header">
</div>
<div id="info">
<div id="recent">
<fieldset>
<legend>Vandaag</legend>
<table border="0">
<tr>
<td>Type</td>
<td>Naam</td>
<td>Reden</td>
<td>Door</td>
<?php
while($a = mysql_fetch_array($vandaag)){
?> <tr>
<td><?php echo($a['Type']);?></td>
<td><?php echo($a['Naam']);?></td>
<td><?php echo($a['Reden']);?></td>
<td><?php echo($a['Door']);?></td>
</tr>
<?php
}
?>
</table>
</fieldset>
</div>
<div id="stats">
<fieldset>
<legend>Turfjesteller</legend>
<table border="0">
<tr>
<td>Naam</td>
<td>Aantal</td>
<td>Gedaan</td>
<td>Resterend</td>
</tr>
<?php
while($r = mysql_fetch_array($names)){
echo("<tr id=".$r['Naam'].">");
?>
<td><?php echo($r['Naam']);?></td>
<?php
$sql="SELECT * FROM turfjes WHERE Naam='".$r['Naam']."' AND Type='Adtje'";
$result=mysql_query($sql);
$count=mysql_num_rows($result); //count = adtjes
$sql2="SELECT * FROM turfjes WHERE Naam='".$r['Naam']."' AND Type='Turfje'";
$result2=mysql_query($sql2);
$count2=mysql_num_rows($result2); //count2 = turfje
?>
<td><?php echo($count2);?></td>
<td><?php echo($count);?></td>
<td><?php echo($count2-$count);?></td>
</tr>
<?php
}
?>
</table>
</fieldset>
</div>
</div>
<div id="actie">
<div id="nieuw">
<fieldset>
<legend>Nieuwe turfjes</legend>
<label>Naam</label>
<select id = "naamnieuw">
<option value="" selected></option>
<?php
while($r = mysql_fetch_array($names2)){
echo("<option value='".$r['Naam']."'>".$r['Naam']."</option>");
}
?>
</select>
<br>
<label>Reden</label> <input type="text" name="redennieuw" id="redennieuw"/> <br>
<label>Door</label> <input type="text" name="door" id="door" disabled="disabled" value =<?php echo($_SESSION['uid']) ?>> <br>
<div id = "buttonz"><button type="button" id="submitnieuw">Turfje uitdelen</button></div>
</fieldset>
</div>
<div id="verwijder">
<fieldset>
<legend>Verwijderen turfjes</legend>
<label>Naam</label>
<select id = "naamverwijder">
<option value="" selected></option>
<?php
while($r = mysql_fetch_array($names3)){
echo("<option value='".$r['Naam']."'>".$r['Naam']."</option>");
}
?>
</select>
<br>
<label>Door</label> <input type="text" name="door" id="door2" disabled="disabled" value =<?php echo($_SESSION['uid']) ?>> <br>
<div id = "buttonz"><button type="button" id="submitdelete">Turfje verwijderen</button></div>
</fieldset>
</div>
<form name="logout" method="post" action="logout.php">
<div id = "buttonz"><input type="submit" name="logout" value="Log uit"></div>
</form>
</div>
</div>
</body>
</html>
测试警报没有执行，所以我知道我的悬停不起作用。我检查并执行悬停之前的所有内容，但仍然有效。
我不太确定我做错了什么。有人可以帮我吗？
根据在线检查员的说法，我的语法似乎很好。