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example_list = ['21.48678', '21.46552', '21.45145', '21.43822',
                '21.42734', '21.41222', '21.40132', '21.37679']

我在将这个列表从字符串转换为整数时遇到了一些麻烦，我也想把它作为整数。谢谢 ：）

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5 回答 5

7

最简单的是

[int(float(x)) for x in your_list]

这将截断所有数字

如果您想对数字进行四舍五入，请改用它

[int(float(x)+.5) for x in your_list]
于 2012-05-29T09:50:33.583 回答
2

首先转换为float 

>>> lst = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']
>>> ints = [int(float(num)) for num in lst]
[21, 21, 21, 21, 21, 21, 21, 21]
于 2012-05-29T09:50:56.507 回答
2 
foo = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']

map(lambda x: int(float(x)), foo)
于 2012-05-29T09:52:06.217 回答
0 
[int(round(float(i))) for i in example_list]

将列表中的项目转换为float，将它们四舍五入，然后将它们转换为int.

于 2012-05-29T11:15:42.003 回答
0 
new_list=[]
for each in example_list:
    Integer = int(each)
    new_list.append(Integer)
print new_list

这对初学者来说很容易理解：D

于 2012-05-29T11:24:05.000 回答