8

我们有支持 ONVIF 协议的网络 IP 摄像机。当我尝试获取其 PTZ 配置时，它给出了 Auth 错误。我在 C 中实现这一点。以下是请求和响应。

要求：

"<?xml version=\"1.0\" encoding=\"UTF-8\"?>" 
  "<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\"" 
  "xmlns:tds=\"http://www.onvif.org/ver20/ptz/wsdl\">" 
  "<soap:Body>"
  "<tds:GetNodes/>" 
  "</soap:Body>" 
  "</soap:Envelope>"

回复：

<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope  xmlns:SOAP-ENV="http://www.w3.org/2003/05/soap-envelope" 
                xmlns:SOAP-ENC="http://www.w3.org/2003/05/soap-encoding"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
                xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
                xmlns:wsa5="http://www.w3.org/2005/08/addressing" 
                xmlns:c14n="http://www.w3.org/2001/10/xml-exc-c14n#" 
                xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" 
                xmlns:ds="http://www.w3.org/2000/09/xmldsig#" 
                xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" 
                xmlns:ptzimg2="http://www.onvif.org/ver10/schema" 
                xmlns:ptzimg3="http://www.w3.org/2005/05/xmlmime" 
                xmlns:ptzimg4="http://docs.oasis-open.org/wsn/b-2" 
                xmlns:ptzimg5="http://docs.oasis-open.org/wsrf/bf-2" 
                xmlns:ptzimg6="http://docs.oasis-open.org/wsn/t-1" 
                xmlns:ptzimg1="http://www.onvif.org/ver20/ptz/wsdl" 
                xmlns:ptzimg7="http://www.onvif.org/ver20/imaging/wsdl" 
                xmlns:ter="http://www.onvif.org/ver10/error">

<SOAP-ENV:Body>
    <SOAP-ENV:Fault>
        <SOAP-ENV:Code>
            <SOAP-ENV:Value>
                SOAP-ENV:Sender
            </SOAP-ENV:Value>
            <SOAP-ENV:Subcode>
                <SOAP-ENV:Value>
                    ter:NotAuthorized
                </SOAP-ENV:Value>
            </SOAP-ENV:Subcode>
        </SOAP-ENV:Code>
        <SOAP-ENV:Reason>
            <SOAP-ENV:Text xml:lang="en">
                Sender Not Authorized
            </SOAP-ENV:Text>
        </SOAP-ENV:Reason>
        <SOAP-ENV:Node>
            http://www.w3.org/2003/05/soap-envelope/node/ultimateReceiver
        </SOAP-ENV:Node>
        <SOAP-ENV:Role>
            http://www.w3.org/2003/05/soap-envelope/role/ultimateReceiver
        </SOAP-ENV:Role>
        <SOAP-ENV:Detail>
            The action requested requires authorization and the sender is not authorized
        </SOAP-ENV:Detail>
    </SOAP-ENV:Fault>
</SOAP-ENV:Body>

如何验证用户身份？谢谢

4

2 回答 2

3

那些需要身份验证的命令。可以像这样添加它们的身份验证标头。 

 snprintf(postData, sizeof(postData),
          "<?xml version=\"1.0\" encoding=\"utf-8\"?>" 
          "<SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://www.w3.org/2003/05/soap-envelope\"" 
          "xmlns:wsse=\"http://docs.oasis-open.org/wss/2004/01/oasis-200401"
          "-wss-wssecurity-secext-1.0.xsd\""  
          "xmlns:wsu=\"http://docs.oasis-open.org/wss/2004/01/oasis-"
          "200401-wss-wssecurity-utility-1.0.xsd\""  
          "xmlns:tds=\"http://www.onvif.org/ver20/ptz/wsdl\">" 
          "<SOAP-ENV:Header><wsse:Security><wsse:UsernameToken>" 
          "<wsse:Username>%s</wsse:Username>" 
          "<wsse:Password Type=\"http://docs.oasis-open.org/wss/2004/01/oasis-"
          "200401-wss-username-token-profile-1.0#PasswordDigest\">"
              "%s</wsse:Password><wsse:Nonce>%s</wsse:Nonce>" 
          "<wsu:Created>%s</wsu:Created></wsse:UsernameToken>"
          "</wsse:Security></SOAP-ENV:Header><SOAP-ENV:Body>" 
          "<tds:GetNodes>" 
          "</SOAP-ENV:Body></SOAP-ENV:Envelope>", 
          username, base64EncDigest, nonce_char, time_char);
于 2012-06-05T10:34:43.613 回答
1

您可以使用带有 WSSE 插件的 gSoap 从 OnVif WDSL 生成您需要的 C++ 客户端代理。

这样做大大简化了我的工作。下面是调用 GetVideoEncoderConfiguration 并读取响应的示例。

_media__GetVideoEncoderConfigurations query;
_media__GetVideoEncoderConfigurationsResponse response;

soap_wsse_add_Security(&mediaProxy);
soap_wsse_add_UsernameTokenDigest(&mediaProxy, NULL, m_username.c_str(), m_password.c_str());

if(mediaProxy.GetVideoEncoderConfigurations(&query, &response) == SOAP_OK)
{
    LogSuccess("GetVideoEncoderConfigurations");
    for(auto it = response.Configurations.begin(); it != response.Configurations.end(); ++it)
    {
        onvif__VideoEncoderConfiguration* videoConf = *it;
        log(I3) << "Name= " << videoConf->Name << ", Encoding=" << videoConf->Encoding << ", Resolution=" << videoConf->Resolution->Width << "x" << videoConf->Resolution->Height;
    }
}
else
    LogError("GetVideoEncoderConfigurations", soap_faultdetail(&mediaProxy));

所以没有手动创建肥皂消息。gSOAP 生成的代码在较低层处理这些问题。当然，生成具有 wsse 支持的工作代码需要 mi 2 天，但手动执行它可能要快 10 倍。如果您对更多信息感兴趣，可以联系我。

于 2012-06-28T05:32:51.327 回答