-1

我正在尝试将其重写为案例陈述：

 SELECT dateadd(day, -@Day, getdate()) AS Dt
    ,COUNT(pkey) AS 'BlockerOut'
  FROM tablename
  WHERE PROJECT='10270' AND RESOLUTION='1'
        AND CREATED>dateadd(day, -(30+@Day), getdate()) AND CREATED<dateadd(day, -@Day, getdate())
        AND PRIORITY='1' AND (DATEDIFF(hour, [CREATED], [RESOLUTIONDATE]))>4) t1
JOIN
(SELECT dateadd(day, -@Day, getdate()) AS Dt
    ,COUNT(pkey) AS 'BlockerIn'
FROM jobissue
WHERE PROJECT='10270' AND RESOLUTION='1'
        AND CREATED>dateadd(day, -(30+@Day), getdate()) AND CREATED<dateadd(day, -@Day, getdate())
        AND PRIORITY='1' AND (DATEDIFF(hour, [CREATED], [RESOLUTIONDATE]))<=4) t2
        ON t1.Dt = t2.Dt

我已经走到了这一步，无法弄清楚如何比列更进一步

SELECT dateadd(day, -@Day, getdate()) AS Dt, 
CASE  
WHEN PRIORITY='1' AND (DATEDIFF(hour, [CREATED], [RESOLUTIONDATE]))<=4 then  (pkey)   end  'BlockerIn'
FROM [jobissue] 
WHERE PROJECT='10270' AND RESOLUTION='1'
AND CREATED>dateadd(day, -(30+@Day), getdate()) AND CREATED<dateadd(day, -@Day, getdate())
group by PRIORITY, CREATED, resolutiondate, pkey

这行得通..但是对于两列我得到一个错误：

SELECT dateadd(day, -@Day, getdate()) AS Dt, 
CASE  
WHEN PRIORITY='1' AND (DATEDIFF(hour, [CREATED], [RESOLUTIONDATE]))<=4 then  (pkey)   'BlockerIn'
WHEN PRIORITY='2' AND (DATEDIFF(hour, [CREATED], [RESOLUTIONDATE]))>24 then  (pkey)   'CriticalOut'
end
FROM jobissue
WHERE PROJECT='10270' AND RESOLUTION='1'
AND CREATED>dateadd(day, -(30+@Day), getdate()) AND CREATED<dateadd(day, -@Day, getdate())
group by PRIORITY, CREATED, resolutiondate, pkey

消息 102，级别 15，状态 1，第 18 行“BlockerIn”附近的语法不正确。

我无法计算出多个列名的语法。请帮帮我？谢谢。

4

1 回答 1

1

这就是我的意思

CASE WHEN PRIORITY='1' then  (ID)   END as 'BlockerIn',
CASE WHEN PRIORITY='2' then  (ID)  END  as 'CriticalOut'

这将创建两个包含值的列。

如果您想要一列具有多个值，您会这样做

CASE WHEN PRIORITY='1' then  'BlockerIn' 
WHEN PRIORITY='2' then  'CriticalOut' END  AS Priority
于 2012-05-28T14:21:33.433 回答