php - 使用 mysql 和 php 计算多列

Question

我有一个包含以下列的销售表

• 姓名
• 类型（学生、成人、工人）
• 销售额（A、B、C、D）
• 成本
• 位置 (1,2,3,4)

我想按名称获取与名称和组相关的类型、销售额和位置的计数，以便我可以将其显示在表格上

是否可以使用查询获取所有分组值>

任何帮助将不胜感激..

Answer 1

使用GROUP BY然后SUM(condition)获取您的计数：

SELECT   name AS Name,
         SUM(type     = 'worker' ) AS Worker,
         SUM(type     = 'student') AS Student,
         SUM(type     = 'adult'  ) AS Adult,
         SUM(sales    = 'A'      ) AS A,
         SUM(sales    = 'B'      ) AS B,
         SUM(sales    = 'C'      ) AS C,
         SUM(sales    = 'D'      ) AS D,
         SUM(location = 1        ) AS Location1,
         SUM(location = 2        ) AS Location2,
         SUM(location = 3        ) AS Location3,
         SUM(location = 4        ) AS Location4
FROM     sales
GROUP BY Name

Answer 2

function getDistributorStat() // One Distributor
{

    $this ->db->select("count(*) ch1 ,
                        sum(c_privi_flag = 'Y') ch2, sum(c_happy1_flag = 'Y') ch3, sum(c_happy2_flag = 'Y') ch4,
                        sum(date(D_JOIN) = CURRENT_DATE) nch1,
                        sum(date(d_privi_activated) = CURRENT_DATE) nch2,
                        sum(date(d_happy1_activated) = CURRENT_DATE) nch3,
                        sum(date(d_happy2_activated) = CURRENT_DATE) nch4"
                        );
    $this->db->from('bc_master');
    $query = $this ->db->get()->row();
    $data['distributors']=$query->ch1;
    $data['privilaged']=$query->ch2;
    $data['happy1']=$query->ch3;
    $data['happy2']=$query->ch4;
    $data['new_distributors']=$query->nch1;
    $data['new_privilaged']=$query->nch1;
    $data['new_happy1']=$query->nch1;
    $data['new_happy2']=$query->nch1;

    return $data;

}