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我只是根据存储在 mysql 表中的数据生成一个 csv 文件。生成的 csv 在 excel 中打开时，看起来基本没问题，但只要它有换行符，excel 就会将数据放在新行上。知道如何防止这种情况吗？

样本数据

line 1 some data
another data

CSV 生成代码：

header("Content-Type: text/csv; charset=UTF-8");
header("Content-Disposition: attachment; filename=\"".$MyFileName."\"");
$filename = $MyFileName;
$handle = fopen("temp_files/".$filename, "r");
$contents = fread($handle, filesize("temp_files/".$filename));
fclose($handle);
echo $contents;  
exit;

我用来摆脱新行的内容片段（没有用）：

$pack_inst = str_replace(',',' ',$get_data->fields['pack_instruction']);
        $pack_inst = str_replace('\n',' ',$pack_inst);
        $pack_inst = str_replace('\r',' ',$pack_inst);
        $pack_inst = str_replace('\r\n',' ',$pack_inst);
        $pack_inst = str_replace('<br>',' ',$pack_inst);
        $pack_inst = str_replace('<br/>',' ',$pack_inst);
        $pack_inst = str_replace(PHP_EOL, '', $pack_inst);
        $pattern = '(?:[ \t\n\r\x0B\x00\x{A0}\x{AD}\x{2000}-\x{200F}\x{201F}\x{202F}\x{3000}\x{FEFF}]|&nbsp;|<br\s*\/?>)+';
        $pack_inst = preg_replace('/^' . $pattern . '|' . $pattern . '$/u', ' ', $pack_inst);
        $content .=','.$pack_inst;
4

2 回答 2

2

根据RFC 4180，如果列的内容包含行分隔符 ( \r\n)、列分隔符 ( ,) 或字符串分隔符 ( ")，则必须将内容括在双引号内"。当你这样做时，你必须"在内容中的所有字符前面加上另一个". 所以下面的 CSV 内容：

1: OK,2: this "might" work but not recommended,"3: new
line","4: comma, and text","5: new
line and ""double"" double quotes"
1: Line 2

将生成 2 行 CSV 数据，第一行包含 5 列。

说了这么多，看看fputcsv()功能。它将为您处理最血腥的细节。

于 2012-05-28T08:53:32.457 回答
1

您显示的不是 CSV生成代码，它只是您用来强制下载到浏览器的代码。无论如何，您需要解决这个问题的功能是fputcsv()，它将自动考虑您编写的将表格数据转换为 CSV 格式的任何代码都可能不会考虑的各种边缘情况。

你说你是基于 MySQL 表中的数据，这里是创建 CSV 文件的基本框架，假设 MySQLi 扩展以程序方式使用：

<?php

  // Connect to database and generate file name here
  $fileName = 'file.csv';

  // Get the data from the database
  $query = "
    SELECT *
    FROM table_name
    WHERE some_column = 'Some Value'
    ORDER BY column_name
  ";
  if (!$result = mysqli_query($db, $query)) {
    // The query failed
    // You may want to handle this with a more meaningful error message
    header('HTTP/1.1 500 Internal Server Error');
    exit;
  } else if (!mysqli_num_rows($result)) {
    // The query returned no results
    // You may want to handle this with a more meaningful error message
    header('HTTP/1.1 404 Not Found');
    exit;
  }

  // Create a temporary file pointer for storing the CSV file
  $tmpFP = fopen('php://temp', 'w+');

  // We'll keep track of how much data we write to the file
  $fileLength = 0;

  // Create a column head row and write first row to file
  $firstRow = mysqli_fetch_assoc($result);
  $fileLength += fputcsv($tmpFP, array_keys($firstRow));
  $fileLength += fputcsv($tmpFP, array_values($firstRow));

  // Write the rest of the rows to the file
  while ($row = mysqli_fetch_row($result)) {
    $fileLength += fputcsv($tmpFP, $row);
  }

  // Send the download headers
  header('Content-Type: text/csv; charset=UTF-8');
  header('Content-Disposition: attachment; filename="'.$fileName.'"');
  header('Content-Length: '.$fileLength);

  // Free some unnecessary memory we are using
  // The data might take a while to transfer to the client
  mysqli_free_result($result);
  unset($query, $result, $firstRow, $row, $fileName, $fileLength);

  // Prevent timeouts on slow networks/large files
  set_time_limit(0);

  // Place the file pointer back at the beginning
  rewind(tmpFP);

  // Serve the file download
  fpassthru($tmpFP);

  // Close the file pointer
  fclose($tmpFP);

  // ...and we're done
  exit;
于 2012-05-28T08:36:14.253 回答