1

使用下面的代码，当我单击并按住bid-up按钮时，它只通过一次代码，我必须再次单击它才能工作。它应该做的是重复代码直到 mouseup 或 mouseleave。我做错了什么？

$('.bid-up').live('mousedown',function() {

    var button = $(this);
    timeoutId = setTimeout(function(){

        var number = button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val();
        var newnumber = number.split('.');
        var on = button.attr('data-on');

        button.siblings('#bid-down').attr('data-on','1');

        if(newnumber[1]<9) {
            var first = newnumber[0];
            var second = parseInt(newnumber[1])+1;
        }

        if(newnumber[1]==9) {
            var first = parseInt(newnumber[0])+1;
            var second = 0;
        }

        var finalnumber = first+'.'+second;
        button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val(finalnumber);

    }, 20);

}).bind('mouseup mouseleave', function() {
    clearTimeout(timeoutId);
});
4

2 回答 2

2

解决方案：使用setIntervalandclearInterval代替 timeout，因为 setTimeout 只执行一次闭包函数，或者setTimeout在你的闭包函数中。

setTimeout在函数本身中使用的示例：

$('.bid-up').live('mousedown',function() {

    var button = $(this);


    function asd(){

        var number = button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val();
        var newnumber = number.split('.');
        var on = button.attr('data-on');

        button.siblings('#bid-down').attr('data-on','1');

        if(newnumber[1]<9) {
        var first = newnumber[0];
        var second = parseInt(newnumber[1])+1;
        }

        if(newnumber[1]==9) {
        var first = parseInt(newnumber[0])+1;
        var second = 0;
        }

        var finalnumber = first+'.'+second;
        button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val(finalnumber);

        timeoutId = setTimeout(asd, 20);
    }

    timeoutId = setTimeout(asd, 20);

}).bind('mouseup mouseleave', function() {
    clearTimeout(timeoutId);
});

使用setIntervalanddata存储间隔 id 的示例。

$('.bid-up').live('mousedown',function() {

    var button = $(this);

    button.data('interval', setInterval(function (){

        var number = button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val();
        var newnumber = number.split('.');
        var on = button.attr('data-on');

        button.siblings('#bid-down').attr('data-on','1');

        if(newnumber[1]<9) {
        var first = newnumber[0];
        var second = parseInt(newnumber[1])+1;
        }

        if(newnumber[1]==9) {
        var first = parseInt(newnumber[0])+1;
        var second = 0;
        }

        var finalnumber = first+'.'+second;
        button.parent('div').siblings('#bid-child-container-2').find('#bid-price').val(finalnumber);
    }, 20));

}).bind('mouseup mouseleave', function() {
    clearInterval(button.data('interval'));
});
于 2012-05-27T08:52:19.267 回答
1

试试这个：http: //jsfiddle.net/R85Xb/

var timeoutId;
function x()
{
        $("#bids").append("x");
        timeoutId = setTimeout(x, 200);
}

$('.bid-up').live('mousedown', function() {

    var button = $(this);
    timeoutId = setTimeout(x, 200);

}).bind('mouseup mouseleave', function() {
    //alert('clear');
    clearTimeout(timeoutId);
});​


<div class="bid-up">here</div>
<div id="bids"></div>​
于 2012-05-27T08:59:36.983 回答