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<form id="form1" runat="server">
<div>

    <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" 
        DataKeyNames="bookname"  Height="504px" 
        Width="289px">
        <Columns>
            <asp:TemplateField HeaderText="image">
                <ItemTemplate>
                    <asp:Image ID="Image1" runat="server" 
                        ImageUrl='<%# String.Format("~/path/to/image/" + Eval("image")) %>' />
                </ItemTemplate>
                <EditItemTemplate>
                    <asp:TextBox ID="TextBox1" runat="server" Text='<%# Eval("image") %>'></asp:TextBox>
                </EditItemTemplate>
            </asp:TemplateField>
            <asp:BoundField DataField="bookname" HeaderText="bookname" ReadOnly="True" 
                SortExpression="bookname" />
            <asp:BoundField DataField="price" HeaderText="price" SortExpression="price" />
        </Columns>
    </asp:GridView>
    <asp:SqlDataSource ID="SqlDataSource1" runat="server" 
        ConnectionString="<%$ ConnectionStrings:ConnectionString %>" 
        SelectCommand="SELECT [image], [bookname], [price] FROM [books]">
    </asp:SqlDataSource>

我的图像字段保存​​在(SQL server 2005)中...并通过文件上传按钮将图像插入数据库...现在我想在gridview中显示数据但不显示图像字段和gridview中显示的其他字段很好,因为其他字段是文本格式。

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3 回答 3

1
<asp:Image ID="Image1" runat="server" ImageUrl='<%# String.Format("~/path/to/image/{0}" , Eval("image")) %>' />   

您的问题是string.Format接受参数并且您正在使用 concat 操作。这里我用过{0} - stands for argument at/for index 0。同样对于多个参数,您可以使用string.Format("{0} {1} {2}",var1,var2,var3).

同样在上面我假设 {0} 将被替换为带有扩展名的文件名,如 abc.png。

<form id="form1" runat="server">
    <div>
       <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" 
            DataKeyNames="bookname"  Height="504px" 
            Width="289px">
            <Columns>
                <asp:TemplateField HeaderText="image">
                    <ItemTemplate>
                        <asp:Image ID="Image1" runat="server" 
                            ImageUrl='<%# String.Format("~/path/to/image/{0}" , Eval("image")) %>' />
                    </ItemTemplate>
                    <EditItemTemplate>
                        <asp:TextBox ID="TextBox1" runat="server" Text='<%# Eval("image") %>'></asp:TextBox>
                    </EditItemTemplate>
                </asp:TemplateField>
                <asp:BoundField DataField="bookname" HeaderText="bookname" ReadOnly="True" 
                    SortExpression="bookname" />
                <asp:BoundField DataField="price" HeaderText="price" SortExpression="price" />
            </Columns>
        </asp:GridView>
        <asp:SqlDataSource ID="SqlDataSource1" runat="server" 
            ConnectionString="<%$ ConnectionStrings:ConnectionString %>" 
            SelectCommand="SELECT [image], [bookname], [price] FROM [books]">
        </asp:SqlDataSource>
于 2012-05-26T22:18:23.453 回答
0

当您的图像存储到数据库中时,您需要使用处理程序来检索图像。您可以在这里获得参考http://www.codeproject.com/Articles/271590/Show-an-image-saved-in-a-SQL-Table-on-an-ASP-Net-I

于 2012-05-26T22:10:32.960 回答
0

我希望像

ImageUrl='<%# this.ResolveUrl("~/path/to/image/" + Eval("image")) %>' />

而不是string.Format

于 2012-05-26T20:05:01.373 回答