3

我使用的 Oracle 数据库包含客户、连锁店和活动表。像这样（精简）：

TABLE CUSTOMER 
  ACCOUNTNUMBER   VARCHAR2
  CHAIN           VARCHAR2
  CATEGORY        VARCHAR2

TABLE CHAIN
  CODE            VARCHAR2
  PARENTCHAIN     VARCHAR2

TABLE CAMPAIGN
  ID              NUMBER
  DISCOUNT        NUMBER

TABLE CAMPAIGN_ELIGIBILITY
  CAMPAIGNID      NUMBER   --ID of the campaign
  ACCOUNTNUMBER   VARCHAR2 --Customer included in the campaign
  CHAINCODE       VARCHAR2 --Chain included in the campaign
  CUSTCATCODE     VARCHAR2 --Customercategory included in the campaign

客户可以通过其定义的客户组或作为连锁店的成员有资格参加特定的活动（基于帐号）。

我使用此查询来查找对给定客户有效的所有活动：

select * from campaign where id in
(
  select unique campaignid from campaign_eligibility where 
    accountnumber=:accountnumber
  union
  select unique campaignid from campaign_eligibility where 
    chaincode = 
      (select chain from debtable where accountnumber=:accountnumber)
  union
  select unique campaignid from campaign_eligibility where 
    custcatcode =
      (select category from customer where accountnumber=:accountnumber)
)

现在，假设客户“Popeye Spinach Empire”是“Spinach Dealers Inc.”连锁店的成员，该连锁店又是较大连锁店“GreenFud R US”的一部分，而后者又是“FoAC”连锁店的一部分”。如果有针对“GreenFud R US”的广告系列，Popeye 就有资格参与该广告系列。我的查询将仅返回已明确添加 Popeye 或以“Spinach Dealers Inc.”为目标的广告系列。

如何修改我的查询以包含客户间接参与的营销活动？

4

1 回答 1

3 
WITH    chains AS
        (
        SELECT  code
        FROM    chain c
        START WITH
                c.code IN
                (
                SELECT  chain
                FROM    campaign_eligibility
                WHERE   accountnumber = :acc
                UNION ALL
                SELECT  chain
                FROM    customer c
                JOIN    campaign_eligibility ce
                ON      ce.custcatcode = c.category
                WHERE   accountnumber = :acc
                UNION ALL
                SELECT  chain
                FROM    customer
                WHERE   accountnumber = :acc
                )
        CONNECT BY
                c.code = PRIOR c.parentchain
        ) ch
SELECT  *
FROM    campaign
WHERE   c.id IN
        (
        SELECT  campaignid
        FROM    chains 
        JOIN    campaign_eligibility ce
        ON      ce.chaincode = c.code
        )
于 2012-05-26T20:13:43.977 回答