我使用 BLOB 将对象插入 SQLite 数据库。插入后,我可以用“SELECT”语句获取数据并且数据是正确的,虽然用“SQLite Database Browser”浏览数据库时“TASK_HEAD”的行是“Empty”。但是,如果我破坏了刚刚插入的对象,就不能再得到正确的数据了,指针“pHead”指向一个地址,其“id”成员的内容是“铪铪铪铪铪铪” " 在调试模式下在 VS2008 中读取时。
这是一个例子:
// user-defined data type
typedef std::string TASK_ID;
struct TASK_HEAD
{
TASK_ID id;
std::string userData;
int Size()
{
return (id.size() + userData.size()) * sizeof(TCHAR);
}
};
// when TEST_INSIDE is defined, pHead is invalid; but if undef it, I can get the "head" I just inserted
// and if the blob data is a string (when USING_STRING is defined), I can get the string inserted into the db even though the "test" string has been destroyed
void CDBWriter::WriteTestData()
{
// open db
sqlite3* db = NULL;
int nRet = sqlite3_open(DATABASE_NAME.c_str(), &db);
if (nRet != SQLITE_OK)
{
return;
}
if (db != NULL)
{
// create a table
std::string cmdCreate("CREATE TABLE IF NOT EXISTS testTable (id TEXT NOT NULL, TASK_HEAD BLOB, PRIMARY KEY(id));");
char* errMsg = NULL;
nRet = sqlite3_exec( db , cmdCreate.c_str() , 0 , 0 , &errMsg );
if( errMsg != NULL )
{
sqlite3_free( errMsg );
errMsg = NULL;
return;
}
//#define USING_STRING
#define TEST_INSIDE
#ifndef TEST_INSIDE
TASK_HEAD head;
#endif // TEST_INSIDE
// insert blob data
const TASK_ID newID(NewGUID()); // NewGUID returns string like this: "5811307F-7AA7-4C44-831F-774FC5832627"
string query = "INSERT OR REPLACE INTO testTable (id, TASK_HEAD) VALUES ('";
query += newID;
query += "', ?1);";
sqlite3_stmt* res = NULL;
nRet = sqlite3_prepare_v2(db, query.c_str(), query.length(), &res, 0);
{
#ifdef TEST_INSIDE
TASK_HEAD head;
#endif // TEST_INSIDE
head.id = newID;
#ifdef USING_STRING
std::string test("ewsjoafijdoaijeofsafsd");
nRet = sqlite3_bind_blob (res, 1, test.c_str(), test.size(), SQLITE_TRANSIENT);
#else
int nsizeHead = sizeof(head);
int nSizeHeadSt = sizeof(TASK_HEAD);
int sizeString = sizeof(std::string);
size_t nLen = newID.size();
//nRet = sqlite3_bind_blob (res, 1, &head, sizeof(head), SQLITE_TRANSIENT);
nRet = sqlite3_bind_blob (res, 1, &head, head.Size(), SQLITE_TRANSIENT);
#endif // USING_STRING
if (SQLITE_OK == nRet)
{
nRet = sqlite3_step(res);
}
if (nRet != SQLITE_OK && nRet != SQLITE_DONE)
{
return;
}
}
// get all columns in the database
query = "SELECT * FROM testTable;";
nRet = sqlite3_prepare_v2 (db, query.c_str(), query.length(), &res, 0);
if (SQLITE_OK == nRet)
{
while (SQLITE_ROW == sqlite3_step(res))
{
#ifdef USING_STRING
const char* pHead = (const char*)sqlite3_column_blob(res, 1);
#else
const TASK_HEAD *pHead = (const TASK_HEAD*)sqlite3_column_blob(res, 1);
#endif // USING_STRING
continue;
}
}
sqlite3_finalize(res);
sqlite3_close(db);
}
}
起初,我认为这可能是传递给 sqlite3_bind_blob 的字节的问题,所以我用一种愚蠢的方法获取对象的字节,正如您在此处看到的(TASK_HEAD 的 size() 函数),但这无济于事. 然后我尝试使用 SQLITE_STATIC 而不是 SQLITE_TRANSIENT,仍然无法正常工作。怎么了?
Ps:我知道将对象插入数据库是一个不好的解决方案,我只想知道为什么我无法读回插入数据库的数据。