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我正在尝试将一个表中的键添加到另一个表中，以便创建一对多关系。我要添加外键的表当前包含员工的名字和姓氏，但没有 ID。我想根据他们的名字和姓氏查询员工表以找到ID，然后将其添加到伤害表中。

我不断收到以下错误：

The multi-part identifier "InjuryOLD.FirstName" could not be bound.
The multi-part identifier "dbo.InjuryOLD.LastName" could not be bound.

下面是 SQL 语句：

Insert into dbo.InjuryOLD(dbo.InjuryOLD.EmpID)
Select dbo.EmployeeInformation.EmpID
From EmployeeInformation
Where exists(select dbo.EmployeeInformation.EmpID from dbo.EmployeeInformation
             where dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
             and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)

我确保我引用的表和列没有错字，而且我知道两个员工可能有相同的名字。但是，在这种情况下并非如此。

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1 回答 1

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语句应始终独立工作的SELECT部分INSERT

所以...

Select dbo.EmployeeInformation.EmpID
From EmployeeInformation
Where exists(select dbo.EmployeeInformation.EmpID from dbo.EmployeeInformation
             where dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
             and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)

...不起作用，因为dbo.InjuryOLD在任何 FROM 子句中都没有引用。您可能打算将dbo.InjuryOLDExists 子查询的 from 子句放入，而不是重复EmployeeInformation 

Select dbo.EmployeeInformation.EmpID
From EmployeeInformation
Where exists(select 1 from dbo.InjuryOLD  
             where
                 dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
                 and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)
于 2012-05-25T17:19:02.653 回答