假设我有一个列表，例如：
lst = ["Line1\r\nLine2\r\n", "Line3\r\nLine4\r\n", etc.]
有没有一种很好的pythonic方法来分割行尾的元素并使它们成为单独的元素，即
new_lst = ["Line1\r\n", "Line2\r\n", "Line3\r\n", "Line4\r\n"]
我知道我可以有几行额外的代码来循环遍历列表，拆分元素并将它们存储在一个新列表中，但我对 python 比较陌生，想养成使用所有很酷的功能，例如列表推导。提前致谢！
>>> lst = ["Line1\r\nLine2\r\n", "Line3\r\nLine4\r\n"]
>>> new_lst = [elem for l in lst for elem in l.splitlines(True)]
>>> new_lst
['Line1\r\n', 'Line2\r\n', 'Line3\r\n', 'Line4\r\n']
import itertools as it
list(it.chain(*(elem.splitlines(True) for elem in lst)))
或者
[line for elem in lst for line in elem.splitlines(True)]
两者都返回：['Line1\r\n', 'Line2\r\n', 'Line3\r\n', 'Line4\r\n']
来自文档：
S.splitlines([keepends]) -> list of strings
Return a list of the lines in S, breaking at line boundaries.
Line breaks are not included in the resulting list unless keepends
is given and true.
这适用于\r\n以及\r和\n。
new_lst = [x + '\r\n' for x in ''.join(lst).split('\r\n')][:-1]
为了完整起见，让我们添加这个丑陋的解决方案；）
new_lst = ('\r\n'.join(lst)).splitlines(True)