我得到hexTouchAreas
了我的方法的返回值-drawHexagonTouchArea
,但是当我分析我的项目时,它所说的行CGMutablePathRef hexTouchArea = CGPathCreateMutable();
会产生一个警告:“在初始化期间存储到 'hexTouchArea' 的值永远不会被读取”。并且在CGPathRelease(hexTouchArea);
它抱怨我不拥有那个对象的那一行,并且释放它是多余的。
另一个警告是在return path;
分析器说的行:“在第 629 行分配并存储到路径(即CGMutablePathRef path = CGPathCreateMutable();
)中的对象的潜在泄漏”
-(void)createTouchAreas{
int realPositionsCount =[[GameStateSingleton sharedMySingleton]getSharedRealCountOfPositions];
hexTouchAreas = [[GameStateSingleton sharedMySingleton]getSharedHexTouchAreas];
NSMutableDictionary *existingHexagons = [[GameStateSingleton sharedMySingleton]getExistingHexagons];
for (int i = 0; i <= realPositionsCount;i++){
//create touchareas
NSString *hexKey = [NSString stringWithFormat:@"hexagon%d", i];
CCSprite *theSprite = [[existingHexagons objectForKey:hexKey]objectForKey:@"realSprite"];
CGPoint touchAreaOrigin = ccp(theSprite.position.x -22, theSprite.position.y-40);
NSString *touchAreaKey = [NSString stringWithFormat:@"hexTouchArea%d",i];
CGMutablePathRef hexTouchArea = CGPathCreateMutable();
hexTouchArea = (CGMutablePathRef) [self drawHexagonTouchArea:touchAreaOrigin];
[hexTouchAreas setObject:(id)hexTouchArea forKey:touchAreaKey];
[[GameStateSingleton sharedMySingleton]setSharedHexTouchAreas:hexTouchAreas];
CGPathRelease(hexTouchArea);
}
}
创建和返回路径的方法:
-(CGMutablePathRef)drawHexagonTouchArea:(CGPoint)origin
{
CGMutablePathRef path = CGPathCreateMutable();
CGPoint newloc = CGPointMake(origin.x, origin.y);
CGPathMoveToPoint(path, NULL, newloc.x, newloc.y);
CGPathAddLineToPoint(path, NULL, newloc.x -22,newloc.y + 38);
CGPathAddLineToPoint(path, NULL, newloc.x + 0, newloc.y + 76);
CGPathAddLineToPoint(path, NULL, newloc.x + 46, newloc.y + 76);
CGPathAddLineToPoint(path, NULL, newloc.x +66,newloc.y + 40);
CGPathAddLineToPoint(path, NULL, newloc.x +44, newloc.y + 0);
CGPathCloseSubpath(path);
return path;
}