android - 如何在 Android SOAP Web 服务中将 InputStream 数据转换为字符串

Question

当我从 Android 使用肥皂网络服务时，我想在输出字符串中显示结果，如何将该输入流转换为 Sting？

  package com.venkattt.pack;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.SocketException;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.AndroidHttpTransport;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParser;
import org.xmlpull.v1.XmlPullParserFactory;

import android.app.Activity;
import android.os.Bundle;

public class SoapWebservicesExampleActivity extends Activity {
    /** Called when the activity is first created. */
      final String NAMESPACE = "urn:sap-com:document:sap:soap:functions:mc-style";
     final String URL = "http://**********:8000/sap/bc/srt/wsdl/srvc_14DAE9C8D79F1EE196F1FC6C6518A345/wsdl11/allinone/ws_policy/document?sap-client=800&sap-user=************&sap-password=*********";
      final String METHOD_NAME = "Z_GET_CUST_GEN";
     final String SOAP_ACTION = "urn:sap-com:document:sap:soap:functions:mc-style/Z_GET_CUST_GEN";
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
           SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); // set up
            request.addProperty("Input", "1460");
            request.addProperty("Langu", "d");
            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12); // put all required data into a soap
            envelope.dotNet = true;
            envelope.setOutputSoapObject(request);
            HttpTransportSE httpTransport = new HttpTransportSE(URL);
            httpTransport.debug = true;

            try {


                 httpTransport.call(SOAP_ACTION, envelope);
                 SoapObject response = (SoapObject)envelope.getResponse();
                 String str = response.getProperty(0).toString();

                 System.out.println("theeeeeeeeeee"+str);



                }
            catch(SocketException ex){
                    ex.printStackTrace();

                } catch (Exception e) {
                   e.printStackTrace();
                }
        }


    }

我的最终代码请看一下并告诉我

我在哪里可以在上面的代码中进行转换？

score 22 · Accepted Answer

   String  response = convertStreamToString(instream);

方法

private String convertStreamToString(InputStream is) {
    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line).append('\n');
        }
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return sb.toString();
}

score 3 · Accepted Answer

阅读行（\n 和 \r；没有区别）可能会造成混乱。要从 InputStream 中获取字符串，我建议您复制/粘贴以下方法并在需要时调用它。

public static String getStringFromInputStream(InputStream stream, String charsetName) throws IOException
{
    int n = 0;
    char[] buffer = new char[1024 * 4];
    InputStreamReader reader = new InputStreamReader(stream, charsetName);
    StringWriter writer = new StringWriter();
    while (-1 != (n = reader.read(buffer))) writer.write(buffer, 0, n);
    return writer.toString();
}

score 2 · Accepted Answer

根据Shane McC 文章，您可以使用此方法：

public String readFully(InputStream entityResponse) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int length = 0;
while ((length = entityResponse.read(buffer)) != -1) {
    baos.write(buffer, 0, length);
}
return baos.toString();
}

score 2 · Accepted Answer

import com.google.android.gms.common.util.IOUtils;

InputStream input = getInputStream();
String body = new String(IOUtils.toByteArray(input), "UTF-8");
input.close();

score 0 · Accepted Answer

你可以这样试试：

SoapObject response = (SoapObject)envelope.getResponse();
String str = response.getProperty(0).toString();

str 将保存内容，您需要根据需要进一步解析它。另外，请查看此链接以及如何解析它的链接。

http://android-devblog.blogspot.com/2010/06/soap-on-android.html

尝试使用肥皂 VER11 而不是 VER12，因为这会出错。

SoapSerializationEnvelope envelope = new  SoapSerializationEnvelope(SoapEnvelope.VER11);

// 将所有需要的数据放入一个soap中

可以从此链接获得更多信息： http ://groups.google.com/group/android-developers/browse_thread/thread/b585862b6e939fd2

score 0 · Accepted Answer

您可以使用：

String response = org.apache.commons.io.IOUtils.toString(instream, "UTF-8");

您需要将 org.apache.commons.io.jar 添加到构建路径。

android - 如何在 Android SOAP Web 服务中将 InputStream 数据转换为字符串

6 回答 6

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