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我的 IPN 脚本有问题。它可以用于验证付款等，但我试图让它将数据输入数据库。之前的用户电子邮件和密码输入工作正常，但不是第二个..

$item_name = $_POST['item_name'];
$item_number = $_POST['item_number'];
$payment_status = $_POST['payment_status'];
$payment_amount = $_POST['mc_gross'];
$payment_currency = $_POST['mc_currency'];
$txn_id = $_POST['txn_id'];
$receiver_email = $_POST['receiver_email'];
$payer_email = $_POST['payer_email'];

$email = $_POST['item_name'];
$password = mt_rand(1000, 9999);
$Random = print_r($_POST);


mysql_query("INSERT INTO users (email, password) VALUES('". mysql_escape_string($email)     ."', '".md5($password)."') ") or die(mysql_error()); 

mysql_query("INSERT INTO LNCH_Sales SET
                                                            item_name = '%s',
                                                            item_number = '%s',
                                                            payment_status = '%s',
                                                            payment_amount = '%s',
                                                            payment_currency = '%s',
                                                                txn_id = '%s',
                                                            receiver_email = '%s',
                                                            payer_email = '%s'",
                                                            mysql_real_escape_string($item['name']),
                                                            mysql_real_escape_string($item['number']),
                                                            mysql_real_escape_string($payment['status']),
                                                            mysql_real_escape_string($payment['amount']),
                                                            mysql_real_escape_string($payment['currency']),       
                                                            mysql_real_escape_string($txn['id']),
                                                            mysql_real_escape_string($receiver['email']),
                                                            mysql_real_escape_string($payer['email'])

                                                                      );

任何想法这里有什么问题？

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2 回答 2

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您的语法错误 - 而不是

INSERT INTO LNCH_SALES SET

（看起来像是 INSERT 和 UPDATE 的混合体），你需要

INSERT INTO LNCH_SALES(<column_list>) VALUES (...
于 2012-05-24T12:18:10.317 回答
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正如@FrankSchmitt 所说，您可能缺少列列表。

您可以跳过列列表的唯一方法是插入列的数量=表列的数量，即：

jcho360> create table test (id int,name varchar(20));
Query OK, 0 rows affected (0.05 sec)

jcho360> insert into test values (1,'Jcho360');
Query OK, 1 row affected (0.00 sec)

jcho360> insert into test values (1);
ERROR 1136 (21S01): Column count doesn't match value count at row 1

jcho360> insert into test(id) values (1);
Query OK, 1 row affected (0.01 sec)

正如您所看到的，只有当我要在“插入”中填充所有列时，您才能跳过列列表。

于 2012-05-24T12:53:55.687 回答