我在 SQLite 中有一个 s3db 数据库。现在我想在应用程序中附加或打开它?请告诉我需要编写什么代码才能连接到数据库?
问问题
1426 次
2 回答
1
I don't know exactly what you want but if you want to get data from your database you can do it like this:
this.database = new ContactsDatabase(this, Contacts.DB_NAME, null, Contacts.startVersion).getWritableDatabase();
this.cursor = this.database.rawQuery("SELECT _id, name, email, phone FROM contacts ORDER BY name ASC", null);
Check official guides.
于 2012-05-24T09:18:54.960 回答
1
我会给你一个例子,你可以很容易地理解我们如何在文本视图上显示数据库中的数据。下面是其中 testdata 是具有用户表的数据库的名称的代码,其中存在 2 列。我在 2 diff 上显示这 2 列的数据。文本视图。
public class high_score extends Activity{
SQLiteDatabase mydatabase=null;
String Data="";
String Data1="";
String TableName="users";
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.high_score);
RelativeLayout main=(RelativeLayout)findViewById(R.id.main);
try
{
mydatabase=this.openOrCreateDatabase("testdata", MODE_PRIVATE, null);
Cursor c=mydatabase.rawQuery("SELECT DISTINCT name,score FROM "+TableName+" , null);
int column1=c.getColumnIndex("name");
int column2=c.getColumnIndex("max_score");
c.moveToFirst();
if(c!=null)
{
do
{
String Name=c.getString(column1);
int Score=c.getInt(column2);
Data=Data+Name+"\n";
Data1=Data1+Score+"\n";
System.out.println("name"+Name+" score"+Score);
}while(c.moveToNext());
TextView tv=(TextView)findViewById(R.id.tv);
TextView points=(TextView)findViewById(R.id.points);
tv.setText(Data);
points.setText(Data1);
setContentView(main);
}
/*TextView tv=(TextView)findViewById(R.id.tv);
tv.setText(Data);
setContentView(tv);*/
}catch(Exception ex)
{
Log.e("ERROR","ERROR" ,ex);
}
finally
{
if(mydatabase!=null)
mydatabase.close();
}
您可以像这样轻松访问数据
于 2012-05-24T09:30:10.950 回答