1

我正在尝试将旧的 VB.NET 应用程序移植到 Android 应用程序，但由于我缺乏 Java 经验，我无法找到这个应用程序。我尝试了多种解决方案，但无济于事。

这个想法基本上是向“http://login.vk.com/”发出 POST 请求并获取响应 cookie。如果有人能给我关于如何在 Android 上使用 cookie 的提示，我将非常感激。

原始代码

    Public Sub Login(ByVal Username As String, ByVal Password As String)
    Try

        ' Make request
        Dim cont As New CookieContainer
        Dim request As HttpWebRequest
        request = WebRequest.Create("http://login.vk.com/")
        request.Method = "POST"
        request.CookieContainer = cont

        ' Create POST content and send
        Dim postdata As String = "act=login&success_url=&fail_url=&try_to_login=1&to=&vk=&al_test=3&email=" & HttpUtility.UrlEncode(Username) & "&pass=" & HttpUtility.UrlEncode(Password) & "&expire="
        Dim postbytes() As Byte = System.Text.Encoding.UTF8.GetBytes(postdata)
        request.ContentType = "application/x-www-form-urlencoded"
        request.ContentLength = postbytes.Length
        Dim requestStream As Stream = request.GetRequestStream
        requestStream.Write(postbytes, 0, postbytes.Length)
        requestStream.Close()

        ' Get response and login cookie
        Dim response As HttpWebResponse = request.GetResponse
        Dim cookies As CookieCollection = request.CookieContainer.GetCookies(New Uri("http://pirate.vk.com"))
        For Each myCookie As Cookie In cookies
            If myCookie.Name = "remixsid" Then
                Me.Guid = myCookie.Value
            End If
        Next
        response.Close()

        ' Throw error if cookie not found
        If Not IsLoggedIn Then Throw New Exception("Invalid login guid")

    Catch ex As Exception
        Throw New Exception("Error at custom login", ex)
    End Try
End Sub

目前写的代码：

                HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://login.vk.com/");

            try {
                List<NameValuePair> postData = new ArrayList<NameValuePair>(); 
                postData.add(new BasicNameValuePair("act", "login"));
                postData.add(new BasicNameValuePair("success_url", ""));
                postData.add(new BasicNameValuePair("fail_url", ""));
                postData.add(new BasicNameValuePair("try_to_login", "1"));
                postData.add(new BasicNameValuePair("to", ""));
                postData.add(new BasicNameValuePair("vk", ""));
                postData.add(new BasicNameValuePair("al_test", ""));
                postData.add(new BasicNameValuePair("email", URLEncoder.encode(username, "UTF-8")));
                postData.add(new BasicNameValuePair("pass", URLEncoder.encode(password, "UTF-8")));
                postData.add(new BasicNameValuePair("expire", ""));
                httppost.setEntity(new UrlEncodedFormEntity(postData));

                HttpResponse response = httpclient.execute(httppost);

            } catch(Exception e) {

            }
4

2 回答 2

1

尝试以这种方式获取 cookie 作为响应：

private static HttpParams params;
params = new BasicHttpParams();
HttpClientParams.setRedirecting(params, false);
HttpClientParams.setCookiePolicy(params, CookiePolicy.BROWSER_COMPATIBILITY);
HttpClient httpclient = new DefaultHttpClient(params);

HttpPost httppost = new HttpPost("http://login.vk.com/");

            try {
                List<NameValuePair> postData = new ArrayList<NameValuePair>(); 
                postData.add(new BasicNameValuePair("act", "login"));
                postData.add(new BasicNameValuePair("success_url", ""));
                postData.add(new BasicNameValuePair("fail_url", ""));
                postData.add(new BasicNameValuePair("try_to_login", "1"));
                postData.add(new BasicNameValuePair("to", ""));
                postData.add(new BasicNameValuePair("vk", ""));
                postData.add(new BasicNameValuePair("al_test", ""));
                postData.add(new BasicNameValuePair("email", URLEncoder.encode(username, "UTF-8")));
                postData.add(new BasicNameValuePair("pass", URLEncoder.encode(password, "UTF-8")));
                postData.add(new BasicNameValuePair("expire", ""));
                httppost.setEntity(new UrlEncodedFormEntity(postData));

                HttpResponse response = httpclient.execute(httppost);
                List<Cookie> cookies = ((DefaultHttpClient)httpclient).getCookieStore().getCookies();
                for(Cookie cookie : cookies){
                Log.i("Cookie", cookie.toString());
             }

            } catch(Exception e) {

            }
于 2012-05-24T02:31:28.083 回答
0

希望这对您有所帮助：

    HttpURLConnection urlConn = null;
//edit String data as what you want
    String data = "act=login&success_url=&fail_url=&try_to_login=1&to=&vk=&al_test=3&email=" & URLEncoder.encode(username, "UTF-8")) & "&pass=" & URLEncoder.encode(password, "UTF-8")) & "&expire="
        URL mUrl;
        StringBuffer response = new StringBuffer(); 
        try {               
            mUrl = new URL("http://login.vk.com/");
            urlConn = (HttpURLConnection) mUrl.openConnection();
            urlConn.setRequestMethod("POST");
            //query is your body
            urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");            
            urlConn.setRequestProperty("Content-Length", Integer.toString(data.length()));
            urlConn.setUseCaches (false);
            urlConn.setDoInput(true);
            urlConn.setDoOutput(true);

            //send request
            DataOutputStream wr = new DataOutputStream (
                    urlConn.getOutputStream ());
            wr.write(data.getBytes("UTF8"));
            wr.flush ();
            wr.close ();

            //Get Response  
            InputStream is = urlConn.getInputStream();
            BufferedReader rd = new BufferedReader(new InputStreamReader(is));
            String line;            
            while((line = rd.readLine()) != null) {
              response.append(line);
              response.append('\r');
            }
            rd.close();
            String result = response.toString();
            return result;
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }  catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }finally {

              if(urlConn != null) {
                  urlConn.disconnect(); 
              }
        }
于 2012-05-24T02:01:04.310 回答