python - 为什么不读取这个“if”语句？

Question

在我的代码中，我希望'Opposite'和'Hypotenuse'这两个答案有两个不同的结果，但是，每当我测试代码并回答'相反'时，它都会忽略其余代码并归结为'斜边的问题。我是否将其格式化/是否有更简单的方法来执行此操作/等等？

from math import *

    def  main():

       #Trignometry Problem

        def answer():
            answer = raw_input()

    while True:

        # Phrase Variables
        phrase1 = ("To begin, we will solve a trigonometry problem using sin.")
        phrase2 = ("Which is known - hypotenuse or opposite?")
        phrase3 = ("Good! Now, we will begin to solve the problem!")
        phrase4 = ("Please press any key to restart the program.")

        print phrase1
        origin=input("What is the origin?")
        print phrase2
        answer = raw_input()
        if answer == ("Hypotenuse.") or ("Hypotenuse") or ("hypotenuse") or ("hyotenuse."):
            hypotenuse=input("What is the hypotenuse?")
            print "So, the problem is " + "sin" + str(origin) + " = " + "x" + "/" + str(hypotenuse) + "?"
            answer = raw_input()
            if answer == ("Yes.") or ("yes") or ("yes.") or ("Yes"):
                print phrase2
            answer = raw_input()
            print phrase4
            answer = raw_input()
            if answer == ("No."):
                break 
        if answer == ("Opposite."):
            opposite=input("What is the opposite?")
            print "So, the problem is " + "sin" + str(origin) +  " = " + str(opposite) + "/" + "x" + "?"
            answer = raw_input()
            if answer == ("Yes.") or ("yes") or ("yes.") or ("Yes"):
                print phrase2
        answer = raw_input()
        print phrase4
        answer = raw_input()
        if answer == ("No."):
            break


    main()

Answer 1

简短的回答

您可能想要更改这些：

if answer == ("Hypotenuse") or ("Hypotenuse.") ...

这样：

if answer in ("Hypotenuse", "Hypotenuse.", ...):

解释

表达方式：

answer == ("Foo") or ("Bar")

它的评估如下：

(answer == ("Foo")) or (("Bar"))

而且"Bar"总是True。

显然，正如评论中指出的那样，"HYPOTENUSE" in answer.upper()是最好的解决方案。