python3中的一个解决方案是:
#Uses python3
import sys
def calc_cache_pos(strings, indexes):
factor = 1
pos = 0
for s, i in zip(strings, indexes):
pos += i * factor
factor *= len(s)
return pos
def lcs_back(strings, indexes, cache):
if -1 in indexes:
return ""
match = all(strings[0][indexes[0]] == s[i]
for s, i in zip(strings, indexes))
if match:
new_indexes = [i - 1 for i in indexes]
result = lcs_back(strings, new_indexes, cache) + strings[0][indexes[0]]
else:
substrings = [""] * len(strings)
for n in range(len(strings)):
if indexes[n] > 0:
new_indexes = indexes[:]
new_indexes[n] -= 1
cache_pos = calc_cache_pos(strings, new_indexes)
if cache[cache_pos] is None:
substrings[n] = lcs_back(strings, new_indexes, cache)
else:
substrings[n] = cache[cache_pos]
result = max(substrings, key=len)
cache[calc_cache_pos(strings, indexes)] = result
return result
def lcs(strings):
if len(strings) == 0:
return ""
elif len(strings) == 1:
return strings[0]
else:
cache_size = 1
for s in strings:
cache_size *= len(s)
cache = [None] * cache_size
indexes = [len(s) - 1 for s in strings]
return (lcs_back(strings, indexes, cache))
if __name__ == '__main__':
input = sys.stdin.read()
data = list(map(int, input.split()))
an = data[0]
data = data[1:]
a1 = data[:an]
data = data[an:]
bn = data[0]
data = data[1:]
b1 = data[:bn]
data = data[bn:]
cn = data[0]
data = data[1:]
c1 = data[:cn]
a = ''
for i in a1:
a = a + i
b = ''
for i in b1:
b = b + i
c = ''
for i in c1:
c = c + i
print(lcs([a, b, c]))
这会读取 3+ 个数组的输入,每个字符后跟一个空格。在每个数组之前输入数组的大小。输入将是
输入:
8
阿巴克达布
6
bdcaba
6
巴卡
输出:
咩