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我正在尝试div.field用父 div 包装每个包含一组 (s) 的对象.row。Jquery 只允许我在同一行打开和关闭父 div。请帮忙！

  $(document).ready(function(){
    $.getJSON('WF-XML.php', function(data) {

        JSON.stringify(data);
        var prevCardCode = '';

        $.each( data, function(index, element){

            if (!(element['CardCode'] == prevCardCode)) {

                var sum = element['payment_sum'];

                    $('#showdata').append('<div class="row"><div class="field">' + sum + '</div>');
                }
                prevCardCode = element['CardCode'];

                $.each(element, function(i, element_detail){
                    if (!(i == 'InvKey' || i == 'PostDate' || i == 'City' || i == 'Objtype' || i == 'Block' || i == 'ZipCode' || i == 'Address' || i == 'payment_sum' || i == 'State1' || i == 'Country' || i == 'NumAtCard')) {
                        var detail = element_detail;
                        $('#showdata').append('<div class="field">' + detail + '</div>');
                    }

                });

           });
    });

});

PHP

  if (($handle = fopen('upload/BEN-new.csv', "r")) === FALSE) {
    die('Error opening file'); 
 }

 $headers = fgetcsv($handle, 1024, ',');
 $complete = array();

      while ($row = fgetcsv($handle, 1024, ",")) {
       $complete[] = array_combine($headers, $row);
        }
    fclose($handle);

    echo json_encode($complete);

这是数据：

 {"InvKey":"11704","CardCode":"1611704", "payment_sum": "1055.40"},
 {"InvKey":"11703","CardCode":"1611703", "payment_sum": "550.00"}

它的打印是这样的：

 <div class="row">
      div class="field">1055.40</div>
 </div>
 <div class="field">1611704</div>
 <div class="row">
 <div class="field">550.00</div>
 </div>
 <div class="field">1611703</div>

我希望它像这样打印：

  <div class="row">
      <div class="field">1055.40</div>
      <div class="field">1611704</div>
  </div>
  <div class="row">
      <div class="field">550.00</div>
      <div class="field">1611703</div>
  </div>
4

2 回答 2

0

尝试将<div class="field">元素添加到<div class="row">元素中。像这样的东西：

$(document).ready(function() {
    $.getJSON('WF-XML.php', function(data) {

        JSON.stringify(data); // NOTE: This doesn't do anything!!
        var prevCardCode = '';
        var newDiv;

        $.each(data, function(index, element) {
            if (element['CardCode'] != prevCardCode) {
                newDiv = $('<div class="row">').appendTo('#showdata');
                var sum = element['payment_sum'];
                $('.field').before(newDiv);
                $(newDiv).append('<div class="field">' + sum + '</div>');
            }
            prevCardCode = element['CardCode'];

            $.each(element, function(i, element_detail) {
                switch (i) {
                    case 'InvKey':
                    case 'PostDate':
                    case 'City':
                    case 'Objtype':
                    case 'Block':
                    case 'ZipCode':
                    case 'Address':
                    case 'payment_sum':
                    case 'State1':
                    case 'Country':
                    case 'NumAtCard':
                        // Do nothing
                        break;

                    default:
                        $(newDiv).append('<div class="field">' + element_detail + '</div>');
                        break;
                }
            });
        });
    });
});

我还在几个地方清理了您的代码（固定缩进并使您的长条更易于阅读）。

另一种方法是构建一个包含要插入到文档中的 HTML的字符串，在构建整个字符串之前不要使用 jQuery。只要你说$('<div>')，jQuery 就会在内存中创建一个 div 元素。如果你想把东西放在创建的元素里面，你必须把它们放在里面。

于 2012-05-23T17:33:58.397 回答
0

很难确定，但我认为你想要这样的东西：

$(function() {
    $.getJSON('WF-XML.php', function(data) {
        var prevCardCode = '';
        $.each( data, function(index, element){
            if (element['CardCode'] !== prevCardCode) {
                //var newDiv = $('<div/>').addClass('row').appendTo('#showdata');
                var newDiv = $('<div class="rowGroup"><div class="row"></div></div>').appendTo('#showdata').find('.row');
                $('<div class="field">' + element['payment_sum'] + '</div>').appendTo(newDiv);
                $.each(element, function(key, val) {
                    if (key !== 'InvKey' && key !== 'PostDate' && key !== 'payment_sum') {
                        $('<div class="field">' + val + '</div>').appendTo(newDiv);
                    }
                });
                prevCardCode = element['CardCode'];
            }
        });
    });
});
于 2012-05-23T18:15:22.637 回答