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我愿意从 http 请求中读取一个简单的 json 文件。这是我试图阅读的 URL:

http://tccdahora.servehttp.com/teste.php

因此,我得到了一种将 URL 转换为 JSON 的方法,但它不起作用,我尝试了许多不同的方法或在帖子中获取标题,但没有成功。

这是方法:

public static JSONArray getPostJSONObject(String url) throws Throwable {

    // faz o POST na pagina php e obtem o inputstream de resposta
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url); // "http://tccdahora.servehttp.com/teste.php"
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    httppost.setHeader("host", url);
    //httppost.setHeader("Content-Type", "application/json");
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity entity = response.getEntity();
    InputStream is = entity.getContent();

    // transforma o que o php printar em uma strigzona
    JSONArray jArray;
    BufferedReader reader = new BufferedReader(new InputStreamReader(
            is, "iso-8859-1"), 8);
    StringBuilder sb = new StringBuilder();
    sb.append(reader.readLine() + "\n");

    String line = "0";
    while ((line = reader.readLine()) != null) {
        sb.append(line + "\n");
    }
    is.close();
    String result = sb.toString();
    Log.e("", result);
    // transformando em uma array de objetos JSON
    jArray = new JSONArray(result);
    return jArray;
}

我做错了什么吗?我收到了错误的请求错误,并且帖子中的字符串返回了一个通知错误的 HTML 代码,而不是我的浏览器显示的 json。

非常感谢您的关注!

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1 回答 1

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删除以下行:

httppost.setHeader("host", url);
于 2012-05-23T18:05:27.103 回答