1

我创建了一个简单的程序，我想用字符串数组中的其他字符替换一些字符。我创建了一个包含一些单词的字符串数组，我想循环每个单词并检查一些字符是否包含，但是当我试图替换这里没有任何反应是我的代码

            string x = "";
            x = "Script friends above about type=text/javascript>BBC.adverts.writeleaderboardtrue) all </script>friends,eating,khaled,khaled,khaled";
 char[] delimiterChars = { ' ', ',', '.', ':', '\t', ':', '$', '=', ';', '<', '>', '!', ';', ']', '[', '"',
                                    '/','=','-','?'};
 string[] words = x.Split(delimiterChars);
            for (int j = 0; j < words.Length; j++)
            {
                words[j] = words[j].ToLower();
            }
 for (int i = 0; i < words.Length; i++)
            {
                for (int j = 0; j < words[j].Length; j++)
                {

                    if (words[i][j]=='a'||words[i][j]=='e'||words[i][j]=='i'||words[i][j]=='o'||words[i][j]=='u'
                        ||words[i][j]=='h'||words[i][j]=='w'||words[i][j]=='y')
                    {
                        words[i].Replace(words[i][j],'0');
                    }
                    else if (words[i][j] == 'b' || words[i][j] == 'f' || words[i][j] == 'p' || words[i][j] == 'v')
                    {
                        words[i].Replace(words[i][j], '1');
                    }

                     else if (words[i][j] == 'c' || words[i][j] == 'g' || words[i][j] == 'j' || words[i][j] == 'k'
                    || words[i][j] == 'q' || words[i][j] == 's' || words[i][j] == 'x' || words[i][j] == 'z')
                {
                    char xx = words[i][j];
                    words[i].Replace(xx, '2');
                    Console.WriteLine(words[i]);
                }
                else if (words[i][j] == 'd' || words[i][j] == 't')
                {
                    words[i].Replace(words[i][j], '3');
                }
                else if (words[i][j] == 'l')
                {
                    words[i].Replace(words[i][j], '4');
                }
                else if (words[i][j] == 'm' || words[i][j] == 'n')
                {
                    words[i].Replace(words[i][j], '5');
                }
                else if (words[i][j] == 'r')
                {
                    words[i].Replace(words[i][j], '6');
                }



}
}
4

3 回答 3

3

您忘记了字符串是不可变的。

words[i].Replace(words[i][j], '1')返回具有替换值的新 String 实例。

您必须将引用分配回新生成的 String 对象：

words[i] = words[i].Replace(words[i][j], '1');
于 2012-05-22T23:11:56.863 回答
2

该.Replace操作不会改变原始字符串。您必须将结果设置回源变量以应用更改。

words[i] = words[i].Replace(words[i][j], '0');

请注意，replace 适用于整个字符串，因此逐个字母搜索每个a,等并调用 replace 是多余的。e你可以这样做：

words[i] = words[i].Replace('a', '0');
words[i] = words[i].Replace('e', '0');
// etc..

或者更好的是，使用正则表达式：

words[i] = Regex.Replace(words[i], "[aeiouhwy]", "0");
words[i] = Regex.Replace(words[i], "[bfvp]", "1");
于 2012-05-22T23:12:04.000 回答
1

您可以使用Regex.Replace以更紧凑和更有效的方式使相同的内容匹配。即，这个：

            for (int j = 0; j < words[j].Length; j++)
            {

                if (words[i][j]=='a'||words[i][j]=='e'||words[i][j]=='i'||words[i][j]=='o'||words[i][j]=='u'
                    ||words[i][j]=='h'||words[i][j]=='w'||words[i][j]=='y')
                {
                    words[i].Replace(words[i][j],'0');
                }

可以用一个简单的正则表达式替换，如下所示：

  Regex re0 = new Regex("[aeiouhwy]"); // match any of this chras
  string changedWord = re0.Replace(word,"0");

你甚至可以Replace像这样链式调用方法：

  Regex re0 = new Regex("[aeiouhwy]"); // match any of this chras
  Regex re1 = new Regex("[bfpv]");
  string changedWord = re0.Replace(word,"0");
  changedWord = re1.Replace(changedWord,"1")

等等。更容易书写和理解，也更高效。

于 2012-05-23T01:43:43.413 回答