怎么能配
$string = "Foo Bar (Any Group - ANY GROUP Baz)";
应返回为“Foo Bar (Any Group - Baz)”
没有暴力是否可以像这里那样替换字符串中的重复字符串?
编辑:*该组可以由 1-4 个单词组成,而每个单词可以匹配[A-Za-z0-9\/\(\)]{1,30}
*分隔符始终是-
怎么能配
$string = "Foo Bar (Any Group - ANY GROUP Baz)";
应返回为“Foo Bar (Any Group - Baz)”
没有暴力是否可以像这里那样替换字符串中的重复字符串?
编辑:*该组可以由 1-4 个单词组成,而每个单词可以匹配[A-Za-z0-9\/\(\)]{1,30}
*分隔符始终是-
在允许的“单词”字符列表中留出空格,以下内容适用于您的示例:
$result = preg_replace(
'%
( # Match and capture
(?: # the following:...
[\w/()]{1,30} # 1-30 "word" characters
[^\w/()]+ # 1 or more non-word characters
){1,4} # 1 to 4 times
) # End of capturing group 1
([ -]*) # Match any number of intervening characters (space/dash)
\1 # Match the same as the first group
%ix', # Case-insensitive, verbose regex
'\1\2', $subject);