0

在 td 之上执行一些计算后，我试图画一个圆圈。当我运行以下代码时，它可以工作：

$('#priority_one').width($('#learning_streams').width());
$('#priority_one').height($('#learning_streams').height());
var priority_one_paper = new Raphael('priority_one', $('#priority_one').width(), $('#priority_one').height());
var priority_one_circle = priority_one_paper.circle((pos.left).toFixed(0), (pos.top).toFixed(0), (width/2).toFixed(0));
priority_one_circle.attr('stroke','#000000');

但是，当我尝试使其动态化（td 根据用户的输入而变化）时，它不再起作用。代码：

function circlePriorityOne() {
    //priority_one is a div absolutely positioned over a table called learning_streams
    //sets size of priority_one based off the table learning_streams
    $('#priority_one').width($('#learning_streams').width());
    $('#priority_one').height($('#learning_streams').height());


    //creates the 'paper' to draw the circle on
    var priority_one_paper = new Raphael('priority_one', $('#priority_one').width(), $('#priority_one').height());

    var main = getMax(priority_one_count); //returns the id of the td to circle
    var pos = $('#'+main).position();
    var width = $('#'+main).width();

    //using toFixed() to get rid of decimals
    var priority_one_circle = priority_one_paper.circle((pos.left).toFixed(0), (pos.top).toFixed(0), (width/2).toFixed(0));
    priority_one_circle.attr('stroke','#000000');
}

看看这有什么问题吗？谢谢。

4

1 回答 1

1

你是对的。.position()获取相对于父元素的当前位置。

您应该改用.offset()，它获取相对于document

编辑
我不太确定，因为我还没有测试过它，但它应该做你想要的^^

var td = $("#td"),
    pos_td = td.offset(),
    table = td.parents("table"),
    pos_table = table.offset();

// td's position relative to table
console.log("left: " + (pos_td.left - pos_table.left));
console.log("top: " + (pos_td.top - pos_td.top));
于 2012-05-22T19:47:34.397 回答