1

我有两个表，用户和产品。我试图自动创建一个新表 TestedProducts，这是用户和产品之间的多对多关系。但是，我收到此错误。

org.apache.jasper.JasperException: javax.ejb.EJBException: The bean encountered a non-application exception; nested exception is: 
<openjpa-1.2.1-r752877:753278 fatal user error> org.apache.openjpa.persistence.ArgumentException: 
"ejb.UserEntity.products<element:interface ejb.Product>" has columns with targets, but OpenJPA does not support any joins on this mapping in this context.

UserEntity 看起来很精简。

long id;

String firstname;
String lastname;
String password;
String email;
String description;

List<Product> products;

public void setId(long id){
    this.id = id;
}

@Id
@GeneratedValue
public long getId() {
    return id;
}

@ManyToMany
@JoinTable(name="TestedProducts", 
joinColumns=
    @JoinColumn(name="usrId", referencedColumnName="id"),
  inverseJoinColumns=
  @JoinColumn(name="prodId", referencedColumnName="id")
  )
  public List<Product> getProducts() {
    return products;
  }

  public void setProducts(List<Product> products) {
    this.products = products;
  }

像这样的 ProductEntity：

long id;

String name;
String description;
String type;

List<User> users;

@ManyToMany(mappedBy="products") 
protected List<User> getUsers() {
    return users;
}

protected void setUsers(List<User> users) {
this.users = users;
}

我跳过了其余的 setter 和 getter。

4

1 回答 1

0

您需要以与在用户实体中相同的方式在产品实体中注释包含用户的列表，只是倒置。我不认为 mappedby 值的处理方式相同。

于 2012-06-03T15:23:18.197 回答