我有一个自定义异常类,继承自boost::exception
如下:
class ConfigurationException : public boost::exception
{
public:
ConfigurationException(const std::string & title, const std::string & message) {
QMessageBox box(QMessageBox::Critical, QString::fromStdString(title), QString::fromStdString( parse(message) ), QMessageBox::Ok);
box.exec();
}
}
它可以从这样的代码中调用:
try {
// Do some stuff here
} catch (std::exception e) {
BOOST_THROW_EXCEPTION( ConfigurationException("Configuration Error", e.what()) );
}
但是,当我尝试编译时,我得到了错误
Libs\boost\include\boost/throw_exception.hpp(58): error C2664:'boost::throw_exception_assert_compatibility' : cannot convert parameter 1 from 'const ConfigurationException' to 'const std::exception &'
Reason: cannot convert from 'const ConfigurationException' to 'const std::exception'
No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
Libs\boost\include\boost/throw_exception.hpp(85) : see reference to function template instantiation 'void boost::throw_exception<E>(const E &)' being compiled
with
[
E=ConfigurationException
]
src\ConfigurationReader.cpp(81) : see reference to function template instantiation 'void boost::exception_detail::throw_exception_<ConfigurationException>(const E &,const char *,const char *,int)' being compiled
with
[
E=ConfigurationException
]
我不太确定为什么它试图将我的异常转换为std::exception
. 有人能告诉我如何抛出这个异常并获取文件、函数等数据吗?(我应该说显然throw ConfigurationException("some title", "some message");
效果很好。