0

我有这个 ArrayList:

 ArrayList<Double> debtList = datasource.debtList;
 ArrayList<Double> feeList = datasource.feeList;

如何在循环中的 TableLayout 中并排打印这两个列表(格式无关紧要)?这是布局:

 TableLayout table = (TableLayout) findViewById(R.id.myTableLayout);
4

3 回答 3

6

好的,你有两个arraylists debtList和feeList,我假设arraylist都包含相同数量的元素,现在遍历这个列表,Create Table Row将两个textViews添加到table row,并将tablerow添加到tableLayout,所以你可以执行以下操作:

ArrayList<Double> debtList = datasource.debtList;
ArrayList<Double> feeList = datasource.feeList;
TableLayout table = (TableLayout) findViewById(R.id.myTableLayout);
for(int i=0;i<debtList.size();i++)
{
    TableRow row=new TableRow(this);
    double debt = debtList.get(i);
    double fee = feeList.get(i);
    TextView tvDebt=new TextView(this);
    tvDebt.setText(""+debt);
    TextView tvFee=new TextView(this);
    tvFee.setText(""+fee);
    row.addView(tvDebt);
    row.addView(tvFee);
    table.addView(row);
}
于 2012-05-22T04:00:05.867 回答
1

如果arrayLists 大小不相等,我已经找到了解决方案。

这是我实现的逻辑:

这是我的活动:

public class TestStringActivity extends Activity {
private ArrayList<String> input1 = new ArrayList<String>();
private ArrayList<String> input2 = new ArrayList<String>();
private TableRow row;
private TableLayout inflate;
private TextView txtcol1, txtcol2;

/** Called when the activity is first created. */
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);

    //Populating the arrayList
    input1.add("1 ");
    input1.add("2 ");
    input1.add("3 ");
    input2.add(" Red");
    input2.add(" Blue");
    input2.add(" Green");
    input2.add(" White");

    inflate = (TableLayout) TestStringActivity.this
            .findViewById(R.id.mytable);

    for (int i = 0, j = 0; i < input1.size() || j < input2.size();) {
        row = new TableRow(TestStringActivity.this);
        txtcol1 = new TextView(TestStringActivity.this);
        if (input1.size() > i) {
            if ((input1.get(i) != null)) {
                txtcol1.setText(input1.get(i));
                i++;
            }
        } else {
            txtcol1.setText("");
        }
        row.addView(txtcol1);

        txtcol2 = new TextView(TestStringActivity.this);
        if ((input2.size() > j)) {
            if (input2.get(j) != null) {
                txtcol2.setText(input2.get(j));
                j++;
            }
        } else {
            txtcol2.setText("");
        }
        this.row.addView(txtcol2);

        inflate.addView(row);

    }

  }
}

这是我的表格布局 main.xml:

<?xml version="1.0" encoding="utf-8"?>
<TableLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/mytable"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content" >

</TableLayout>

如果 arrayLists 大小不相等,希望这会有所帮助。

于 2012-05-22T05:19:33.583 回答
0

假设 s 中的条目数ArrayList等于 s 中的单元格数TableLayout,您可以尝试以下操作:

int index = 0;
TableLayout tableLayout = findViewById(R.id.table_layout);

for(int n = 0, s = tableLayout.getChildCount(); n < s; ++n) {
    double debt = debtList.get(index);
    double fee = feeList.get(index);

    TableRow row = (TableRow) tableLayout.getChildAt(n);
    TextView cell = (TextView) row.findViewById(R.id.textview_cell);

    name.setText("debt = " + debt + ", fee = " + fee);
    index++;
}
于 2012-05-22T03:47:13.593 回答