mysql - MySQL COUNT 天

Question

我想在图表中获取访问我页面 10 天的用户的价值。我需要 COUNT() 过去十天的所有值。

最好的布局是

Day|COUNT(ip)

1 - 10
2 - 12
3 - 52
......

我希望你明白我的意思。MySQL 可以直接执行此操作，还是需要我在 PHP 中以 10 个单独的查询执行此操作？

问候，莫里茨

使用表结构更新：

    Id (Auto Increment)|Time (Unix Timestamp)|Ip|Referer

Answer 1

这将为您提供具有实际日期值的结果：

SELECT
    COUNT(DISTINCT ip),
    FROM_UNIXTIME(Time, '%m/%d/%Y') AS Day
FROM
    tbl
WHERE
    Time >= UNIX_TIMESTAMP(DATE_ADD(CURDATE(), INTERVAL -10 DAY))
GROUP BY
    FROM_UNIXTIME(Time, '%m/%d/%Y')

Answer 2

这应该为您快速运行

SELECT COUNT(ip) ipcount,dt FROM
(
    SELECT ip,DATE(FROM_UNIXTIME(`Time`)) as dt FROM mytable
    WHERE `Time` > TO_UNIXTIME(NOW() - INTERVAL 10 DAY)
) A GROUP BY dt;

确保你有一个索引Time

ALTER TABLE mytable ADD INDEX TimeIndex (`Time`);

Answer 3

试试这个：

SELECT CAST(DATE(FROM_UNIXTIME(`Time`)) AS CHAR) as dateoftime, COUNT(Ip) as cnt
FROM tablename
WHERE DATE(FROM_UNIXTIME(`Time`)) > DATE_SUB(current_timestamp, INTERVAL 10 DAY)
GROUP BY CAST(DATE(FROM_UNIXTIME(`Time`)) AS CHAR)