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我的搜索功能

     <?php
    $i=0;
    $column_name = 'title'; // column to search by
    $k =$_GET['k'];
    $terms = explode(" ",$k);
    //connect before calling mysql_real_escape_string
    mysql_connect("localhost","","");
    mysql_select_db("test");
    $query ="SELECT bookid,title,author 
    FROM  books WHERE";
    foreach ($terms as $each){
        $i++;
        $each = '%' . $each . '%'; // add wildcard
        $each = mysql_real_escape_string($each); // prevent sql injection
        if($i==1)
            $query .= " $column_name LIKE '$each' ";
        else
            $query .= " OR $column_name LIKE '$each' ";

    }

    echo 'QUERY: ' . $query;

    $query = mysql_query($query) OR DIE(mysql_error());

//Code below is for using the relationships table assuming you have a column name id that
//references to the relationships table. Also, you should add a index on the column id.

$results = "";

while($row = mysql_fetch_array($query)) {
  $results .= '<li>
                <a href="book-relationships.php?id='.$row['id'].'">'.$row['title'].'  author: '.$row['author'].'</a>
              </li>';
}

$results = '<ul>' . $results . '</ul>';

echo $results;

我需要帮助在搜索时将一个数据库与另一个链接起来，这个数据库列出了所有在搜索中出现的书籍，然后将它们与另一个名为关系的表进行比较，并打印出与搜索的书籍有关系的书籍的标题。

当搜索运行时，这是在浏览器中产生的

QUERY: SELECT id,title,author FROM books WHERE title LIKE '%jarrads%' Unknown column 'id' in 'field list'

任何帮助将不胜感激我 100% 被卡住了

图式

书籍 - bookid、title、author、yearpublished、publisher..... 关系 - relationshipid、bookOne、bookTwo、关系、relationshiplikes、relationshipdislikes

bookOne 和 bookTwo，与 bookid 相关

4

1 回答 1

0

您的查询中有错误，因为错误消息指出：

Unknown column 'id' in 'field list'

检查您的表格books以获取有效字段的列表。实现此目的的一种方法是运行以下查询：

SHOW CREATE TABLE books;

于 2012-05-21T15:50:19.447 回答