在谷歌搜索如何在谷歌地图 v3 上旋转自定义标记图像 4-5 小时后,我在这里发布了这个问题。请通过示例提出任何解决方案。
问问题
8604 次
3 回答
2
Code byuser1884506
非常有用,但它会旋转默认图标。
您无法旋转自定义图像。参考 https://developers.google.com/maps/documentation/javascript/3.exp/reference#Symbol
符号的路径,即内置符号路径,或使用 SVG 路径表示法表示的自定义路径。必需的。
为此,您需要使用 SVG(可缩放矢量图形)创建图像。
于 2013-10-01T08:20:21.437 回答
1
请参考以下代码
<script type="text/javascript" >
function kh(i, j, k) {
var a;
var b;
if (j != null && k != null) {
a = j;
b = k;
}
else {
a = 12.9540112248064; b = 77.6991748809814;
}
if (i != null) {
var angleDegrees = i;
}
else {
angleDegrees = 0;
}
var angle = 45;
var myLatlng = new google.maps.LatLng(a, b);
var mapOptions = {
zoom: 16,
center: myLatlng,
mapTypeId: google.maps.MapTypeId.ROADMAP
}
var map = new google.maps.Map(document.getElementById("map_canvas"), mapOptions);
var arrowIcon = new Image();
arrowIcon.src = "../Image/CarNew.png";
var image = '../Image/add.jpg';
var myLatLng = new google.maps.LatLng(a, b);
var beachMarker = new google.maps.Marker({
position: myLatLng,
map: map,
icon: {
path: google.maps.SymbolPath.FORWARD_OPEN_ARROW,
scale: 2,
rotation: angleDegrees }
});document.getElementById("HiddenField1").value=a;
document.getElementById("HiddenField2").value = b;
}
于 2012-12-07T06:22:53.260 回答
-5
using System;
using System.Collections;
using System.Configuration;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.IO;
public partial class NewFolder1_Rotatev3 : System.Web.UI.Page
{
string line;
System.IO.StreamReader file = null;
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
file = new System.IO.StreamReader("D:\\GoogleMapsDemo\\Files\\closepoints.txt");
ScriptManager.RegisterStartupScript(Page, typeof(Page), "_ShowHideBusiJust_", "i();", true);
Session["file"] = file;
}
}
protected void Timer1_Tick(object sender, EventArgs e)
{
file = (System.IO.StreamReader)Session["file"];
string[] strdata = null;
line = file.ReadLine();
if (line != null)
{
strdata = line.Split('\t');
string j = strdata[0];
string k = strdata[1];
Session["Lat"] = j;
Session["Long"] = k;
int R = 6371; // km
double lat1 =HiddenField1.Value != null ? Convert.ToDouble(HiddenField1.Value) : 0;
double lat2 = Convert.ToDouble(j);
double lon1 = HiddenField2.Value != null ? Convert.ToDouble(HiddenField2.Value) : 0;
double lon2 =Convert.ToDouble(k);
if (!(lat2 == 0 && lon2 == 0))
{
var dLat = DegreeToRadian((lat2 - lat1));
var dLon = DegreeToRadian((lon2 - lon1));
lat1 = DegreeToRadian(lat1);
lat2 = DegreeToRadian(lat2);
var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) +
Math.Sin(dLon / 2) * Math.Sin(dLon / 2) * Math.Cos(lat1) * Math.Cos(lat2);
var c = 2 * Math.Atan2(Math.Sqrt(a), Math.Sqrt(1 - a));
var d = R * c;
var y = Math.Sin(dLon) * Math.Cos(lat2);
var x = Math.Cos(lat1) * Math.Sin(lat2) -
Math.Sin(lat1) * Math.Cos(lat2) * Math.Cos(dLon);
var brng = (Math.Atan2(y, x));
var last = RadianToDegree(brng);
Label2.Text = Convert.ToString(d);
string i = Convert.ToString(last);
Session["Angle"] = i;
string script = string.Format("i({0},{1},{2});",
i.ToString(), j.ToString(), k.ToString());
ClientScript.RegisterStartupScript(this.GetType(), "RefreshOpener", script, true);
//System.Threading.Thread.Sleep(1000);
//strdata[0] - Latitude
//strdata[1] - Langitude
}
}
else
{
string i = Convert.ToString(Session["Angle"]);
string j = Convert.ToString(Session["Lat"]);
string k = Convert.ToString(Session["Long"]);
string script = string.Format("i({0},{1},{2});",
i.ToString(), j.ToString(), k.ToString());
ClientScript.RegisterStartupScript(this.GetType(), "RefreshOpener", script, true);
Timer1.Enabled = false;
}
Session["file"] = file;
}
private double DegreeToRadian(double angle)
{
return Math.PI * angle / 180.0;
}
private double RadianToDegree(double angle)
{
return angle * (180.0 / Math.PI);
}
}
于 2013-01-15T06:20:49.050 回答