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我有一个数字和阿尔法的混合列表。

import random

def main():
 list: ['1','2','3','4','5','6','7','a','b','c']

 for count in range (1,5):
   serial_no=("serial #: ", count)
   totallist=0

   from random import choice:
   number=choice(list)

   print(serial_no+'for the time: '+number)

   if number.isdigit() and number<4:
      totallist+=int(number) # want to add the first number >4

   elif number.isdigit()and number>4:
      totallist+=int(number)

   elif number.isalpha():
      list[9]=0
      list[-1]=0
      totallist=int(list[9])+int(list[-1]) #I could not add (error) (want to add alpha(as 0) and number after being alpha)
   print(totallist)

main()

有什么办法可以将第一个随机数> 4 添加到 number < 4 的总随机数中？

谢谢

4

1 回答 1

1

我不知道这是否是您想要的，但这与我可以修复您的语法错误和格式并猜测您想要实现的目标一样接近（希望在A这里付出努力）：

import random

def safe_index(li, i):
   try:
      return li[i]
   except:
      return 0

def main():
   list = ['1','2','3','4','5','6','7','a','b','c']
   totallist = []

   for count in range (1,5):
      serial_no = "serial #%s: " % count

      number = random.choice(list)

      print('%s for the time: %s' % (serial_no, number))

      if number.isdigit() and int(number) < 4:
         print('<4')

         # add digit to first number in series >= 4
         totallist.append(int(number) + 
                          safe_index(filter(lambda x: x >= 4, totallist), 0))

      elif number.isdigit() and int(number) >= 4:
         print('>=4')
         totallist.append(int(number))

      elif number.isalpha():
         print('alpha')

         # convert alpha to ordinal number
         totallist.append(ord(number) - (ord('a') - 1))

   print(totallist)

if __name__ == "__main__":
    main()

样本输出：

serial #1:  for the time: 5
>=4
serial #2:  for the time: 2
<4
serial #3:  for the time: 6
>=4
serial #4:  for the time: a
alpha
[5, 7, 6, 1]
于 2012-05-20T10:51:54.683 回答