我目前有一个使用 UI 自动完成功能的代码,并且似乎显示了我从我的 mysql DB 获得的正确数据。现在我想通过能够接受超过 1 个值来使事情复杂化。我已经上下搜索了互联网,但仍然无法修复我的代码以工作,我是 jquery 的新手,特别是自动完成功能。这是我到目前为止所拥有的..
$('#companyautocomplete').autocomplete({
source: function(request, response) {
//separator: ' ',
$.ajax({
url: "company_search.php",
dataType: "json",
data: {
name_startsWith: request.term,
term: $('#companyautocomplete').val(),
},
success: function(data) {
response($.map(data, function(item) {
return {
compid: item.compid,
label: item.value + ' (' + item.address + ', ' + item.city + ', ' + item.state + ', ' + item.zipcode + ')',
value: item.value,
address: item.address + ', ' + item.city + ', ' + item.state + ', ' + item.zipcode,
phone: item.phone,
problematic: item.problematic
}
}))
},
});
},
select: function(event, ui) {
$('#companyautocomplete').val(ui.item.value);
$('#companyid').val(ui.item.compid);
$('#c_address').val(ui.item.address);
$('#c_phone').val(ui.item.phone);
if (ui.item.problematic!=1){
$('#companyautocomplete').removeClass("ui-autocomplete-error");
document.getElementById('Sendbutton').style.display="block";
} else {
$('#companyautocomplete').addClass("ui-autocomplete-error");
document.getElementById('Sendbutton').style.display="none";
}
}
});
这是我从 company_search.php 得到的回复...
[{"compid":"36","value":"MCDONALD OF ALL SAINTS RD","address":"9261 all saints rd","phone":"","problematic":"0","zipcode":"20723","city":"Laurel","state":"MD","completeaddress":"9261 all saints rd, Laurel, MD, 20723"},{"compid":"37","value":"MCDONALD OF BOWIE","address":"4306 nw CRAIN HWY","phone":"","problematic":"0","zipcode":"20716","city":"Bowie","state":"MD","completeaddress":"4306 nw CRAIN HWY, Bowie, MD, 20716"}]
到目前为止,这一切都按我的意愿工作,但它不接受超过 1 个值,我该如何实现呢?提前致谢 !!