java - ListFragment如何获取listView？

Question

我正在将我的应用程序从 AsyncTasks 移植到 Fragments。

但是如何访问我的片段中的 listView (id: list) 元素？

class MyFragment extends ListFragment {
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        View v = inflater.inflate(R.layout.list_fragment, container, false);
        ListView listView = getListView(); //EX: 
        listView.setTextFilterEnabled(true);
        registerForContextMenu(listView);
        return v;
    }
}

xml:

        <ListView
        android:id="@android:id/list"
        android:layout_width="match_parent"
        android:layout_height="match_parent" >
    </ListView>

前任：

Caused by: java.lang.IllegalStateException: Content view not yet created

Answer 1

正如onCreateView医生留下的：

creates and returns the view hierarchy associated with the fragment

因此，由于该方法没有返回，您将无法访问ListViewthrough getListView()。onActivityCreated您可以在回调中获取有效的引用。或者你可以尝试使用v.findViewById(android.R.id.list)如果在ListView里面声明list_fragment.xml

Answer 2

从视图中获取列表视图，您越来越早了。

View view = inflater.inflate(android.R.layout.list_content, null);
    ListView ls = (ListView) view.findViewById(android.R.id.list);
    // do whatever you want to with list.

Answer 3

这个问题最简单和更可靠的解决方案是覆盖 onActivityCreated(); 并在那里进行列表操作。

@Override
public void onActivityCreated(Bundle savedInstanceState) {
    ListView listView = getListView(); //EX: 
    listView.setTextFilterEnabled(true);
    registerForContextMenu(listView);
    super.onActivityCreated(savedInstanceState);
}

Answer 4

我可以通过 OnViewCreated 方法访问 ListView。

Answer 5

ListFragment listFrag = new ListFragment(){
        @Override
        public void onViewCreated(View view, Bundle savedInstanceState) {
            super.onViewCreated(view, savedInstanceState);
            ListView list = getListView();
            // DO THINGS WITH LIST
        }
    };