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我有一个大问题，我的代码中没有任何错误。该程序应从字段中添加两个值p1并将p2它们上传到站点，而无需重新加载整个页面。我是用简单的 javascript 完成的，但我想使用 AJAX。一切都已经完成，但某处存在小错误。

我看validate()and insterter()，警报具有适当的价值

 alert("data = "+data);
 req.send(data);

但是来自 insterter 的味精是空的。我不知道为什么。请帮忙。我想更正这段代码。

var msg = req.responseText;
        alert("msg = "+msg);

为什么 msg 为空的原因是什么？

@WebServlet("/Serwlet")
public class Serwlet extends HttpServlet {
private static final long serialVersionUID = 1L;
static String KOD =

"<html>"+
"<head>"+
 "<meta http-equiv=\"Content-Type\" content=\"text/html; charset=windows-1250\">"+
"<title>Testowanie</title>"+
"<script type=\"text/javascript\" language=\"javascript\" src=\"servletD2Script.js\"></script>"+
"</head>"+
"<body>"+
"<div id=\"msg1\">Pierwsza suma</div>"+
"<div id=\"msg2\">Pierwsza suma</div>"+
"<center><h2>Testowanie parametrów</h2></center>"+
"<hr>"+
"<form method=\"get\" action=\"Serwlet\">"+
"p1<input type=\"text\" size=\"50\" name=\"p1\" onblur=\"validate()\"><br>"+
"p2<input type=\"text\" size=\"50\" name=\"p2\" onblur=\"validate()\"><br>"+
"<br><input type=\"submit\" value=\"Wyślij formularz by GET\">"+
"</form>"+
"</hr>"+
"<hr>"+
"<form method=\"post\" action=\"Serwlet\">"+
"p3<input type=\"text\" size=\"50\" name=\"p3\" onblur=\"funkcja()\"><br>"+
"p4<input type=\"text\" size=\"50\" name=\"p4\" onblur=\"funkcja()\"><br>"+
"<br><input type=\"submit\" value=\"Wyślij formularz by POST\">"+
"</form>"+
"</hr>"+

"</body></html>";

public Serwlet() {
    super();

}
static boolean raz = true;
private void serviceRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

      response.setContentType("text/html");
      response.setHeader("Cache-Control", "no-cache");
      PrintWriter out = response.getWriter();
      if(raz){out.print(Serwlet.KOD);raz = false;}
      String name = request.getParameter("name");   // dostaję nazwisko
      String org = ""; //jakas wartosc 
      out.write(org != null ?  org : "");    // zwracam organizację lub pusty napis, jesli nie znam nazwiska
}


protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    serviceRequest( request, response);
}


protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    serviceRequest( request, response);
}

}

var req;

function validate() {
//var idField = document.getElementById("name");
var wrt1 = document.getElementById("p1").value;
var wrt2 = document.getElementById("p2").value;
var data = eval(wrt1)+eval(wrt2)+"";

if (typeof XMLHttpRequest != "undefined") {
    req = new XMLHttpRequest();
} else if (window.ActiveXObject) {
    req = new ActiveXObject("Microsoft.XMLHTTP");
}
var url = "Serwlet";
req.open("POST", url, true);      
req.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
alert("data = "+data);
req.send(data);
req.onreadystatechange = inserter;
}




function inserter() {
if (req.readyState == 4) {
    if (req.status == 200) {
        var msg = req.responseText;
        alert("msg = "+msg);
        if (msg == "") {
            document.getElementById("msg1").innerHTML = "<div style=\"color:red\">"+"MSG WAS EMPTY"+"</div>";
            //document.getElementById("msg1").value = "blabla";
        }
        else
            document.getElementById("msg1").innerHTML = "<div style=\"color:red\">"+msg+"</div>";
            //document.getElementById("msg1").value = "COOOO JEST";
    }
}
}

这部分代码总是被调用味精是“”

if (msg == "") {
        document.getElementById("msg1").innerHTML = "<div style=\"color:red\">"+"MSG WAS EMPTY"+"</div>";
        //document.getElementById("msg1").value = "blabla";
    }
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1 回答 1

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raz似乎只有一次，所以下次您输入 servlet 时，您不会在 if 语句中输入，也不会 print Serwlet.KOD。

然后我不明白：

  String org = ""; //jakas wartosc 
  out.write(org != null ?  org : "")

它总是打印一个空字符串，它没用。

serviceRequest以 . 结尾的方法也是一个好习惯out.close();。

于 2012-05-19T08:15:31.233 回答