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我是 android 新手,当我按下第一个按钮时,我如何创建两个按钮,它会转到下一页并获取用户输入并将其存储到 sqlite 数据库中,然后按下第二个按钮,它会从数据库中获取存储的数据并显示数据在表格视图中

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1 回答 1

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研究这个例子,它显示了来自 sqlite 的记录,一个简单的教程。

import java.util.ArrayList;

import android.app.ListActivity;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteException;
import android.os.Bundle;
import android.util.Log;
import android.widget.ArrayAdapter;

public class CRUDonDB extends ListActivity {

    private final String SAMPLE_DB_NAME = "myFriendsDb";
    private final String SAMPLE_TABLE_NAME = "friends";

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);


        ArrayList<String> results = new ArrayList<String>();
        SQLiteDatabase sampleDB = null;

        try {
            sampleDB =  this.openOrCreateDatabase(SAMPLE_DB_NAME, MODE_PRIVATE, null);

            sampleDB.execSQL("CREATE TABLE IF NOT EXISTS " +
                    SAMPLE_TABLE_NAME +
                    " (LastName VARCHAR, FirstName VARCHAR," +
                    " Country VARCHAR, Age INT(3));");

            sampleDB.execSQL("INSERT INTO " +
                    SAMPLE_TABLE_NAME +
                    " Values ('Makam','Sai Geetha','India',25);");
            sampleDB.execSQL("INSERT INTO " +
                    SAMPLE_TABLE_NAME +
                    " Values ('Chittur','Raman','India',25);");
            sampleDB.execSQL("INSERT INTO " +
                    SAMPLE_TABLE_NAME +
                    " Values ('Solutions','Collabera','India',20);");

            Cursor c = sampleDB.rawQuery("SELECT FirstName, Age FROM " +
                    SAMPLE_TABLE_NAME +
                    " where Age > 10 LIMIT 5", null);

            if (c != null ) {
                if  (c.moveToFirst()) {
                    do {
                        String firstName = c.getString(c.getColumnIndex("FirstName"));
                        int age = c.getInt(c.getColumnIndex("Age"));
                        results.add("" + firstName + ",Age: " + age);
                    }while (c.moveToNext());
                } 
            }

            this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,results));

        } catch (SQLiteException se ) {
            Log.e(getClass().getSimpleName(), "Could not create or Open the database");
        } finally {
            if (sampleDB != null) 
                sampleDB.execSQL("DELETE FROM " + SAMPLE_TABLE_NAME);
                sampleDB.close();
        }
    }
}
于 2012-05-19T05:19:54.157 回答