3

我一直在试验hibernate、spring和servlet。现在，我被困住了。为什么我会收到此异常？我认为当 hbm2ddl.auto 设置为创建时会自动创建表。

应用上下文.xml

<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="org.apache.derby.jdbc.ClientDriver" />
    <property name="url" value="jdbc:derby://localhost:1527/db;create=true" />
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="packagesToScan" value="org.springpractice.domain" />
    <property name="hibernateProperties">
        <props>
            <prop key="dialect">
                org.hibernate.dialect.DerbyTenSevenDialect</prop>
            <prop key="show_sql">true</prop>
            <prop key="cache.provider_class">
                org.hibernate.cache.NoCacheProvider</prop>
            <prop key="hbm2ddl.auto">create</prop>
        </props>
    </property> 
</bean>

用户详细信息.java

package org.springpractice.domain;

@Entity
public class UserDetails {

    @Id @GeneratedValue
    protected int id;
    protected String name;
    protected String email;

    // setters/getters ...
}

主.java

@WebServlet("/")
public class Main extends HttpServlet {
    private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        PrintWriter pw = response.getWriter();
        pw.println("hello from servlet");

        UserDetails user = new UserDetails();
        user.setEmail("bob.smith@gmail.com");
        user.setName("Bob Smith");

        ApplicationContext beanFactory =
            WebApplicationContextUtils
                .getRequiredWebApplicationContext(getServletContext());
        SessionFactory sessionFactory = (SessionFactory)     beanFactory.getBean("sessionFactory");
        Session session = sessionFactory.openSession();
        session.save(user);
        session.close();

    }

}

例外

org.hibernate.exception.SQLGrammarException: Table/View 'USERDETAILS' does not exist.
org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
org.hibernate.engine.jdbc.internal.proxy.ConnectionProxyHandler.continueInvocation(ConnectionProxyHandler.java:146)
org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:81)
$Proxy10.prepareStatement(Unknown Source)
...
4

2 回答 2

5

属性名称应以 hibernate 为前缀。

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="packagesToScan" value="org.springpractice.domain" />
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">
                org.hibernate.dialect.DerbyTenSevenDialect</prop>
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.cache.provider_class">
                org.hibernate.cache.NoCacheProvider</prop>
            <prop key="hibernate.hbm2ddl.auto">create</prop>
        </props>
    </property> 
</bean>

顺便说一句，有一种更简单的方法来配置属性，如下所示

    <property name="hibernateProperties">
        <value>
            hibernate.dialect=org.hibernate.dialect.DerbyTenSevenDialect
            hibernate.show_sql=true
            hibernate.cache.provider_class=org.hibernate.cache.NoCacheProvider
            hibernate.hbm2ddl.auto"=create
        </value>
    </property>
于 2012-05-19T11:14:38.327 回答
1

尝试使用注释注释您的实体@Table("USERDETAILS")和所有字段@Column。

参考http://www.vaannila.com/spring/spring-hibernate-integration-1.html Hibernate 是否会自动在数据库中创建表 Hibernate hbm2ddl.auto 可能的值以及它们的作用？

于 2012-05-19T05:11:37.710 回答