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首先,让我解释一下,我很清楚这个例外意味着什么,如果你要回答,请仔细阅读这个问题。

我知道当您尝试在网络线程上进行 UI 工作时会出现异常。我正在使用 AsyncTask,但我正在执行任何 UI 操作。

这是抛出错误的 AsyncTask 代码的片段注意 aps 和 adm 是提前声明的,它在 Extracter 初始化中抛出了异常:

    do{
            try{

                HttpPost request = new HttpPost(params[0]);
                request.setHeader("Accept", "application/json");
                request.setHeader("Content-type", "application/json");
                aps.setLastSent(lastSent);
                StringEntity filterEntity = new StringEntity(aps.TempParameter()); //Remember this TempParameter is temporary function
                request.setEntity(filterEntity);
                response = httpClient.execute(request);
                StatusLine statusLine = response.getStatusLine();
                if(statusLine.getStatusCode() == HttpStatus.SC_OK){
                    Extracter extracter = new Extracter(response);
                    lastSent = extracter.extractLastSent();
                    adm.addDictionary(extracter.extractDictionary());
                }
            } catch (ClientProtocolException e) {
                //TODO Handle problems..
                builder.append("Client protocol exception");
            } catch (IOException e) {
                //TODO Handle problems..
                builder.append(e.toString());
            }
        }while(lastSent != "done");

            return adm.getAlarmObjectList();

线

    Extracter extracter = new Extracter(response);

是抛出异常的地方。下面是 Extracter 类的代码:

    public class Extracter extends AlarmLoopTestActivity {



private JSONObject jo;
private JSONArray ja;

public Extracter(HttpResponse response){
    StringBuilder builder = new StringBuilder();
    HttpEntity entity = response.getEntity();
    try {
        InputStream content = entity.getContent();
        BufferedReader reader = new BufferedReader(new InputStreamReader(content));
        String line;
        while((line = reader.readLine())!= null){
            builder.append(line);
        }
    } catch (IllegalStateException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    String json = builder.toString();
    try {
        jo = (JSONObject) new JSONTokener(json).nextValue();
        ja = jo.getJSONArray("effectNamesDict");
    } catch (JSONException e) {
        jo = null;
        e.printStackTrace();
    }

}

我假设 printStackTrace 不被视为 UI 事件。除此之外,我很茫然。我需要对此有新的认识。如果我需要进一步详细说明,请告诉我。

4

1 回答 1

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Extracter正在扩展一个AlarmLoopTestActivity名称为“这是一个 android Activity”的类,因此它可能有一些 UI 交互方法!

于 2012-05-18T23:17:43.813 回答