11

使用 Google 地方信息时,我可以将搜索限制在城市的街道上Autocomplete吗?

4

4 回答 4

6

您可以设置Autocomplete要用作类型的选项geocode,这将限制返回到地址的结果:

var input = document.getElementById( 'searchTextField' );
var options = {
  bounds: yourBounds,
  types: ['geocode']
};

autocomplete = new google.maps.places.Autocomplete( input, options );

没有办法将结果限制在街道上,但这将在很大程度上实现您想要的。如果您设置yourBounds正确,可能仅限于城市区域,它将让您尽可能接近。

更新回复评论:

如果您想从输入城市开始,您可以将地图的边界绑定到Autocompletes 边界,当在 中选择城市时,地图会自动设置其视口Autocomplete

var options = {
  bounds: yourBounds,
  types: ['(cities)']
};
autocomplete =
    new google.maps.places.Autocomplete( input, options );
// This will bind the map's bounds to the Autocomplete's bounds:
autocomplete.bindTo('bounds', map);

然后,您可以更新Autocomplete的类型,类似于上面,让它返回地址:

autocomplete.setTypes( [ "geocode" ] );

从那里,您可以阅读Places Library API Docs

于 2012-05-18T14:12:37.930 回答
4

只是 html 代码的一个例子(twitter bootstrap 3 compatible :))

<div class="well container">
    <form role="form">
      <div class="form-group">
        <label for="locality" class="sr-only">Stadt oder PLZ</label>
          <input type="text" class="form-control" id="locality" name="locality" placeholder="Stadt oder PLZ" />
          <p class="help-block">Bitte zuerst die Stadt oder PLZ eingeben.</p>
      </div>
      <div class="form-group">
        <label for="route" class="sr-only">Straße / Hausnummer</label>
        <div class="row">
          <div class="col-xs-6">
            <input type="text" class="form-control col-xs-8" id="route" name="route" placeholder="Straße" disabled="true" />
          </div>
          <div class="col-xs-6">
            <input type="text" class="form-control col-xs-4" id="street_number" name="street_number" placeholder="Nr." disabled="true" />
          </div>
        </div>
      </div>
    </form>
</div>

我认为代码是不言自明的,只需尝试一下

<script>
var localityInput = document.getElementById('locality');
var localityOptions = {
  types: ['geocode'], //['(cities)'], geocode to allow postal_code if you only want to allow cities then change this attribute
  componentRestrictions: {country: 'de'}
};
autocomplete = new google.maps.places.Autocomplete(localityInput, localityOptions);

google.maps.event.addListener(autocomplete, 'place_changed', function() {
    $('#route').attr('disabled', false).focus();
    $('#street_number').attr('disabled', false);

    var boundsByCity = autocomplete.getPlace().geometry.viewport;
    var routeInput = document.getElementById('route');
    var routeOptions = {
        bounds: boundsByCity,
        types: ['geocode']
    };
    new google.maps.places.Autocomplete(routeInput, routeOptions);
});
</script>

演示:JSFIDDLE

另一个更高级的演示

于 2014-11-05T18:18:11.560 回答
3

将类型设置为区域

var input = document.getElementById( 'searchTextField' );

var options = {
  bounds: yourBounds,
  types: ['(regions)']
};

autocomplete = new google.maps.places.Autocomplete( input, options );

希望能帮助到你..

于 2015-11-13T14:16:12.000 回答
2

我正在寻找一种方法来将地方自动完成限制为street_number水平,但没有找到。

我能想出的最佳解决方案是检查street_number位置结果中的组件,并在它丢失时向用户显示通知。

示例代码:

var searchbox = document.getElementById('location');

var options = {             
    types: ['geocode']
};

autocomplete = new google.maps.places.Autocomplete(searchbox, options);

google.maps.event.addListener(autocomplete, 'place_changed', function() {
        var place = autocomplete.getPlace();

        var foundStreet = false;

        for (var i = 0; i < place.address_components.length; i++) {
            var c = place.address_components[i];

            for (var j = 0; j < c.types.length; j++) 
            {
                if (c.types[j] == "street_number")
                {
                    foundStreet = true;
                    break;
                }
            }

            if (foundStreet)
                break;
        }

        if (!foundStreet)
            alert("Not a valid street number, add some pretty message to the user.");

        console.log(place);
    });
于 2013-07-09T14:41:43.943 回答