15

我必须维护一个没有文档的旧项目，并且有一个包含很多表和函数以及存储过程的数据库。我想在表和存储过程之间建立一个依赖树，例如，这个过程执行这些过程并使用这些表。

  1. 有什么工具可以帮助我

  2. 如果没有，这些算法的起点是什么？我的意思是我可以从数据库中获取所有过程的源代码，然后解析它以获取所有“exec #”、“update #”、“insert into #”等等。在这种情况下，解决这个问题的最佳方法是什么（可能是正则表达式，或者一些特殊算法......）？

4

5 回答 5

17

Higarian，您的代码对我非常有用。我对其进行了一些改进，以消除循环依赖，包括表引用，并按 ObjectPath 排序。

;with ObjectHierarchy ( Base_Object_Id , Base_Cchema_Id , Base_Object_Name , Base_Object_Type, object_id , Schema_Id , Name , Type_Desc , Level , Obj_Path) 
as 
    ( select  so.object_id as Base_Object_Id 
        , so.schema_id as Base_Cchema_Id 
        , so.name as Base_Object_Name 
        , so.type_desc as Base_Object_Type
        , so.object_id as object_id 
        , so.schema_id as Schema_Id 
        , so.name 
        , so.type_desc 
        , 0 as Level 
        , convert ( nvarchar ( 1000 ) , N'/' + so.name ) as Obj_Path 
    from sys.objects so 
        left join sys.sql_expression_dependencies ed on ed.referenced_id = so.object_id 
        left join sys.objects rso on rso.object_id = ed.referencing_id 
    where rso.type is null 
        and so.type in ( 'P', 'V', 'IF', 'FN', 'TF' ) 

    union all 
    select   cp.Base_Object_Id as Base_Object_Id 
        , cp.Base_Cchema_Id 
        , cp.Base_Object_Name 
        , cp.Base_Object_Type
        , so.object_id as object_id 
        , so.schema_id as ID_Schema 
        , so.name 
        , so.type_desc 
        , Level + 1 as Level 
        , convert ( nvarchar ( 1000 ) , cp.Obj_Path + N'/' + so.name ) as Obj_Path 
    from sys.objects so 
        inner join sys.sql_expression_dependencies ed on ed.referenced_id = so.object_id 
        inner join sys.objects rso on rso.object_id = ed.referencing_id 
        inner join ObjectHierarchy as cp on rso.object_id = cp.object_id and rso.object_id <> so.object_id 
    where so.type in ( 'P', 'V', 'IF', 'FN', 'TF', 'U') 
        and ( rso.type is null or rso.type in ( 'P', 'V', 'IF', 'FN', 'TF', 'U' ) ) 
        and cp.Obj_Path not like '%/' + so.name + '/%' )   -- prevent cycles n hierarcy
select   Base_Object_Name 
    , Base_Object_Type
    , REPLICATE ( '   ' , Level ) + Name as Indented_Name 
    , SCHEMA_NAME ( Schema_Id ) + '.' + Name as object_id 
    , Type_Desc as Object_Type 
    , Level 
    , Obj_Path 
from ObjectHierarchy as p 
order by Obj_Path
于 2017-01-16T14:01:42.153 回答
8

在这里， max(level) 应该可以解决您的问题而无需外部工具

;WITH   cte ( [ID] ,IDSchema,Nome,Tipo,level, SortCol)
AS     (SELECT [so].[object_id] AS ID
               ,so.[schema_id],so.[name],so.[type]
               ,0 AS [Level]     
               ,CAST ([so].[object_id] AS VARBINARY (MAX)) AS SortCol
          FROM [sys].[objects] so
            LEFT JOIN  sys.sql_expression_dependencies ed ON [ed].[referenced_id]=[so].[object_id]
            LEFT JOIN [sys].[objects] rso ON rso.[object_id]=[ed].referencing_id
            --in my database, if i insert tables on the search, it gets more tham 100 levels of recursivity, and that is bad
        WHERE [rso].[type]  IS NULL AND [so].[type] IN ('V','IF','FN','TF','P')

        UNION ALL
        SELECT [so].[object_id] AS ID
            ,so.[schema_id],so.[name],so.[type]
               ,Level + 1
               ,CAST (SortCol + CAST ([so].[object_id] AS BINARY (4)) AS VARBINARY (MAX))
        FROM   [sys].[objects] so
               INNER JOIN  sys.sql_expression_dependencies ed ON [ed].[referenced_id]=[so].[object_id]
               INNER JOIN [sys].[objects] rso ON rso.[object_id]=[ed].referencing_id
               INNER JOIN cte AS cp ON rso.[object_id] = [cp].[ID]
            WHERE [so].[type] IN ('V','IF','FN','TF','P')
            AND  ([rso].[type] IS NULL OR  [rso].[type]  IN ('V','IF','FN','TF','P'))
            )

--CTE
SELECT  ID, IDSchema,
    REPLICATE('   ',level)+nome AS Nome,'['+SCHEMA_NAME(IDSchema)+'].['+nome+']' AS Object,Tipo,Level,SortCol
FROM     cte AS p
ORDER BY  sortcol
于 2015-03-20T19:21:33.267 回答
7

有像 redgate 这样的付费工具，但如果你愿意，你可以随时右键单击一个对象并选择“查看依赖项”。

于 2012-05-18T12:42:12.550 回答
5

您可以使用如下所示的 sys.dm_sql_referenced_entities 来获取任何对象的所有依赖项

SELECT * FROM sys.dm_sql_referenced_entities('dbo.myStoredProcedure', 'OBJECT')

于 2012-05-18T12:50:10.987 回答
0

有人提到了 Redgate 的付费插件。ApexSQL 是另一家为 SQL Server 制作附加组件的公司。其中一些需要花钱，但其他一些是免费的，仍然非常有用。

ApexSQL 搜索是免费的搜索之一。它的2个主要特点是：

  1. 允许您在数据库的数据或结构中搜索某些文本。
  2. 可以为一个或多个对象（您想要的）构建依赖关系的图形树。

安装后，只需右键单击对象或数据库并单击View dependencies（靠近底部，旁边有一个图标）。不要混淆它View Dependencies（靠近顶部，旁边没有图标），它是 SQL Server 中内置的。我发现层次图布局是最有用的。

链接：

于 2017-08-10T21:05:05.630 回答