我正在尝试使用 http api 请求创建一个新的交换。我用来创建 Exchange 的 URL 是 ,http://guest:guest@localhost:55672/api/exchanges/%2F/myexq1
但它给了我 401 Unauthorized 错误。我正在使用 chrome rest 客户端来执行此请求。可能是什么原因?任何帮助将不胜感激。
问问题
3173 次
1 回答
2
有其他方式解决问题。使用 URL 时出现错误http://guest:guest@localhost:55672/api/exchanges/%2F/myexq1
。但为了实现我的目标,我写了一个小班。这是代码:
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpHost targetHost = new HttpHost("xx.xx.xx.xx", 55672, "http");
HttpPut request = new HttpPut(
"/api/queues/%2F/q1");
httpClient.getCredentialsProvider().setCredentials(
new AuthScope(targetHost.getHostName(), targetHost.getPort()),
new UsernamePasswordCredentials("guest", "guest"));
AuthCache authCache = new BasicAuthCache();
BasicScheme basicAuth = new BasicScheme();
authCache.put(targetHost, basicAuth);
BasicHttpContext localcontext = new BasicHttpContext();
localcontext.setAttribute(ClientContext.AUTH_CACHE, authCache);
request.addHeader("Content-Type", "application/json");
StringEntity input = new StringEntity(
"{\"vhost\":\"/\",\"durable\":\"false\",\"auto_delete\":\"false\",\"arguments\":{}}");
request.setEntity(input);
HttpResponse response = httpClient.execute(targetHost, request, localcontext);
我包括的罐子是:
commons-codec-1.4
commons-logging-1.1.1
httpclient-4.1.3
httpclient-cache-4.1.3
httpcore-4.1.4
httpmime-4.1.3
于 2012-05-19T06:35:35.843 回答