2

我正在使用以下代码与 ssl 服务器执行 ssl 握手和证书验证。

import ssl
import socket

s = socket.socket()
print "connecting..."
#logging.debug("Connecting")
# Connect with SSL mutual authentication
# We only trust our server's CA, and it only trusts user certificates signed by it
c = ssl.wrap_socket(s, cert_reqs=ssl.CERT_REQUIRED,
                    ssl_version=ssl.PROTOCOL_SSLv3, ca_certs='ca.crt',
                    certfile='user.crt', keyfile='user.key')
c.connect((constants.server_addr, constants.port))

我能够连接到服务器并且证书得到正确验证,但是,我不确定从这里做什么。我需要通过套接字执行 https 操作,包括将 XML 发布到 REST API。我该怎么做?

4

3 回答 3

1

您可以使用您的wrap_socket代码进行扩展httplib.HTTPConnection,如本答案中所述。

(我仍然会考虑使用 PycURL 之类的东西,正如我在你之前的问题中已经回答的那样。)

于 2012-05-17T18:10:15.147 回答
0

您可能想从以下位置开始urllib2.urlopenhttp ://docs.python.org/library/urllib2.html#urllib2.urlopen

这可以处理 https URL、获取、发布等。您不需要直接在低级别socketssl对象上工作。但是,如果您使用的是 Python 2.x,HTTPS 连接不会对服务器端证书进行任何验证,这看起来像是您需要的(这很好)。不过, Python 3urllib确实做到了这一点。

如果您使用的是 Python 2,那么您有几个选择。一种是子类urllib2.HTTPSHandler化,以便对其套接字进行适当的验证。另一种是自己实现需要的HTTP协议位(不推荐)。您也可以正常实例化各种对象,urllib2然后httplib简单地分配您已经过身份验证的 ssl 套接字来代替它们正在使用的那些,尽管您需要非常小心,以免它们的状态被弄乱。不过,标准库中的源代码非常易读,以防您需要像这样进行修改。

于 2012-05-17T17:59:04.213 回答
0

这正是我在项目中所做的。这是我在项目中使用的 REST 客户端模块。它已根据我的需要进行了修改,但我认为您可能会发现它也很有用。它需要 httplib2: http: //pypi.python.org/pypi/httplib2

"""
    client.py
    ---------

    Modified to allow validation server's certificate with external cacert list.
    -- Arif Widi Nugroho <arif@sainsmograf.com>

    Copyright (C) 2008 Benjamin O'Steen

    This file is part of python-fedoracommons.

    python-fedoracommons is free software: you can redistribute it and/or modify
    it under the terms of the GNU General Public License as published by
    the Free Software Foundation, either version 3 of the License, or
    (at your option) any later version.

    python-fedoracommons is distributed in the hope that it will be useful,
    but WITHOUT ANY WARRANTY; without even the implied warranty of
    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    GNU General Public License for more details.

    You should have received a copy of the GNU General Public License
    along with python-fedoracommons.  If not, see <http://www.gnu.org/licenses/>.
"""

__license__ = 'GPL http://www.gnu.org/licenses/gpl.txt'
__author__ = "Benjamin O'Steen <bosteen@gmail.com>, Arif Widi Nugroho <arif@sainsmograf.com>"
__version__ = '0.1'

import httplib2
import urlparse
import urllib
import base64
from base64 import encodestring

from mime_types import *

import mimetypes

from cStringIO import StringIO

class Connection(object):
    def __init__(self, base_url, username=None, password=None, cache=None, ca_certs=None, user_agent_name=None):
        self.base_url = base_url
        self.username = username
        m = MimeTypes()
        self.mimetypes = m.get_dictionary()

        self.url = urlparse.urlparse(base_url)

        (scheme, netloc, path, query, fragment) = urlparse.urlsplit(base_url)

        self.scheme = scheme
        self.host = netloc
        self.path = path

        if user_agent_name is None:
            self.user_agent_name = 'Basic Agent'
        else:
            self.user_agent_name = user_agent_name

        # Create Http class with support for Digest HTTP Authentication, if necessary
        # self.h = httplib2.Http(".cache")
        self.h = httplib2.Http(cache=cache, ca_certs=ca_certs)
        self.h.follow_all_redirects = True
        if username and password:
            self.h.add_credentials(username, password)

    def request_get(self, resource, args = None, headers={}):
        return self.request(resource, "get", args, headers=headers)

    def request_delete(self, resource, args = None, headers={}):
        return self.request(resource, "delete", args, headers=headers)

    def request_head(self, resource, args = None, headers={}):
        return self.request(resource, "head", args, headers=headers)

    def request_post(self, resource, args = None, body = None, filename=None, headers={}):
        return self.request(resource, "post", args , body = body, filename=filename, headers=headers)

    def request_put(self, resource, args = None, body = None, filename=None, headers={}):
        return self.request(resource, "put", args , body = body, filename=filename, headers=headers)

    def get_content_type(self, filename):
        extension = filename.split('.')[-1]
        guessed_mimetype = self.mimetypes.get(extension, mimetypes.guess_type(filename)[0])
        return guessed_mimetype or 'application/octet-stream'

    def request(self, resource, method = "get", args = None, body = None, filename=None, headers={}):
        params = None
        path = resource
        headers['User-Agent'] = self.user_agent_name

        BOUNDARY = u'00hoYUXOnLD5RQ8SKGYVgLLt64jejnMwtO7q8XE1'
        CRLF = u'\r\n'

        if filename and body:
            #fn = open(filename ,'r')
            #chunks = fn.read()
            #fn.close()

            # Attempt to find the Mimetype
            content_type = self.get_content_type(filename)
            headers['Content-Type']='multipart/form-data; boundary='+BOUNDARY
            encode_string = StringIO()
            encode_string.write(CRLF)
            encode_string.write(u'--' + BOUNDARY + CRLF)
            encode_string.write(u'Content-Disposition: form-data; name="file"; filename="%s"' % filename)
            encode_string.write(CRLF)
            encode_string.write(u'Content-Type: %s' % content_type + CRLF)
            encode_string.write(CRLF)
            encode_string.write(body)
            encode_string.write(CRLF)
            encode_string.write(u'--' + BOUNDARY + u'--' + CRLF)

            body = encode_string.getvalue()
            headers['Content-Length'] = str(len(body))
        elif body:
            if not headers.get('Content-Type', None):
                headers['Content-Type']='text/xml'
            headers['Content-Length'] = str(len(body))        
        else: 
            headers['Content-Type']='text/xml'

        if method.upper() == 'POST':
            headers['Content-Type']='application/x-www-form-urlencoded'

        if args:
            path += u"?" + urllib.urlencode(args)

        request_path = []
        if self.path != "/":
            if self.path.endswith('/'):
                request_path.append(self.path[:-1])
            else:
                request_path.append(self.path)
            if path.startswith('/'):
                request_path.append(path[1:])
            else:
                request_path.append(path)

        resp, content = self.h.request(u"%s://%s%s" % (self.scheme, self.host, u'/'.join(request_path)), method.upper(), body=body, headers=headers )

        return {u'headers':resp, u'body':content.decode('UTF-8')}

示例用法(如果服务器证书未由指定的 ca 签名,则连接将失败):

c = client.Connection('https://localhost:8000', certs='/path/to/cacert.pem')
# now post some data to the server
response = c.request_post('rest/path/', body=some_urlencoded_data)
if response['headers']['status'] == '200':
    # do something...
于 2012-05-18T07:42:11.800 回答