python-3.x - Create a program that takes a parameter a two-dimensional list of integers and returns True if each row of the table sums up to an odd number

Question

Any help would be greatly appreciated. As you can see from what I have so far, my knowledge of the python language is...well...weak.

example:

oddrow([[1, 2], [9, 4], [7, 6]])
True

def oddrow(lst):
  for item in lst:
    if sum(item[0:n]) #lost

Answer 1

Try the all built-in:

Return True if all elements of the iterable are true (or if the iterable is empty).

So a list comprehension can map the oddness of the sum of the elements of one inner list into boolean space - e.g. the result for [[1, 2], [9, 4], [7, 6]] would look like [True, True, True]. And all will do the rest.

def oddrow(lst): 
    return all([ sum(l) % 2 == 1 for l in lst ])

# since it's short, why not just make it a one-liner
oddrow = lambda lst: all([ sum(l) % 2 == 1 for l in lst ])