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我有 2 个单独的选择语句，每个语句都使用聚合函数。我希望能够获取结果并将它们结合起来。

table_a
id int
entered_date datetime (holds utc stamp)
balance money
group_id int

table_b
id int
entered_date date
balance money
transaction_type int

query 1: 
select convert(date,entered_date), sum(balance) as earned
from table_a
where group_id in (1, 2, 3, 4)
group by convert(date,entered_Date)

query 2: 
select convert(date,entered_date), sum(balance) as spent
where transaction_type = 2
group by convert(date,entered_Date)

results:
query 1:
2012-05-13, 5000
2012-05-14, 12000
...

query 2:
2012-05-13, 9000
2012-05-14, 55856
...

我想在不使用临时表的情况下为每条记录返回一行。结果集应该有一个日期，然后是收入与花费。我有一个使用联合运行的报告来获取总数，这很好，但我需要生成一个包含 1 条记录和一个赚到的对比线的结果集。对此的任何帮助表示赞赏。

4

4 回答 4

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尝试：

;With AllDates AS
(
select convert(date,entered_date) As EnteredDate
    from table_a
    where group_id in (1, 2, 3, 4)
    group by convert(date,entered_Date)
UNION
select convert(date,entered_date)
    from table_b
    where transaction_type = 2
    group by convert(date,entered_Date)
)
, AllEarned AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Earned
    from table_a
    where group_id in (1, 2, 3, 4)
    group by convert(date,entered_Date)
)
, AllSpent AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Spent
    from table_b
    where transaction_type = 2
    group by convert(date,entered_Date)
)
SELECT
    d.EnteredDate, e.Earned, s.Spent
    FROM AllDates d
    LEFT OUTER JOIN AllEarned e ON d.EnteredDate=e.EnteredDate
    LEFT OUTER JOIN AllSpent s ON d.EnteredDate=s.EnteredDate
    ORDER BY 1,2,3
于 2012-05-17T02:56:04.800 回答
0 
SELECT 
       CASE WHEN a.a_date IS NULL THEN b.a_date ELSE a.a_date END as a_data, 
       a.earned,
       b.spent
FROM
    (select 
         convert(date,entered_date) as a_date, 
         sum(balance) as earned
    from table_a
    where group_id in (1, 2, 3, 4)
    group by entered_Date) A
FULL OUTER JOIN 
   (select 
        convert(date,entered_date) as a_date, 
        sum(balance) as spent
    from table_a
    where transaction_type = 2
    group by entered_Date) B 
ON A.a_date=b.a_date

或者FULL OUTER JOIN如果有数据不满足这两个条件，则使用。并使用CASE WHEN a.a_date IS NULL THEN b.a_date ELSE a.a_date END as a_data

于 2012-05-17T02:57:48.040 回答
0

Assuming earned amounts are from table_a and spent amounts are from table_b,

; WITH a AS (
    select entered_date=convert(date,entered_date), balance as earned, 0 AS spent
    from table_a
    where group_id in (1, 2, 3, 4)
    UNION ALL
    select entered_date=convert(date,entered_date), 0 AS earned, balance as spent
    from table_b
    where transaction_type = 2
)
SELECT entered_date
, earned=SUM(earned)
, spent=SUM(spent)
FROM a
GROUP BY entered_date
于 2012-05-17T04:12:52.000 回答
0

您可以使用逻辑组合这些，假设两者都来自同一个表（第二个查询缺少 from 语句）：

select convert(date,entered_date),
       sum(case when group_id in (1, 2, 3, 4) then balance end) as earned,
       sum(case when transaction_type = 2 then balance end) as spend
from table_a
group by convert(date,entered_Date)
于 2012-05-17T03:00:37.887 回答