python - 如何将元组元素作为参数传递给函数？

Question

我有一个由元组组成的列表，我想将每个元组的元素作为参数传递给函数：

mylist = [(a, b), (c, d), (e, f)]

myfunc(a, b)
myfunc(c, d)
myfunc(e, f)

我该怎么做？

Answer 1

这实际上在 Python 中非常简单，只需遍历列表并使用 splat 运算符 ( *) 将元组解包为函数的参数：

mylist = [(a, b), (c, d), (e, f)]
for args in mylist:
    myfunc(*args)

例如：

>>> numbers = [(1, 2), (3, 4), (5, 6)]
>>> for args in numbers:
...     print(*args)
... 
1 2
3 4
5 6

Answer 2

要明确@DSM 的评论：

>>> from itertools import starmap
>>> list(starmap(print, ((1,2), (3,4), (5,6)))) 
# 'list' is used here to force the generator to run out.
# You could instead just iterate like `for _ in starmap(...): pass`, etc.
1 2
3 4
5 6
[None, None, None] # the actual created list;
# `print` returns `None` after printing.